2 years ago

ASAP ANZWER PleASEEE :)

Mathematics

1 answer:

Hitman42 [59]2 years ago

5 0

Answer:

%80

Step-by-step explanation:

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The price of a pair of Jordans was reduced from $200 to $160. By percentage was the price reduced

hichkok12 [17]

Answer:

20%

Step-by-step explanation:

3 0

2 years ago

The scatter plot shows the number of stamps Katie collected in different months:. . Plot ordered pairs 1, 30 and 2, 70 and 3, 11

Virty [35]

The sequence:
a 1 = 30, a 2 = 70, a 3 = 110, a 4 = 150, a 5 = 190,...
a 2 = a 1 + d
70 = 30 + d
d = 70 - 30 = 40
a n = a 1 + ( n - 1 ) * d
For the 25th month:
a 25 = 30 + 24 * 40 = 30 + 960 = 990
Answer: B ) 990.

3 0

2 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

2 years ago

Can somebody please help me with this question

Zanzabum

Answer:

Step-by-step explanation:

6 0

2 years ago

How many solutions does the equation x^2-9x=-8 have?

Elza [17]

X^2-9x=-8
x^2-9x+8=-8+8
x^2-9x+8=0
(x-8)(x-1)=0

x-8=0
x-8+8=0+8
x=8

x-1=0
x-1+1=0+1
x=1

There are 2 solutions, which are 1 and 8

8 0

2 years ago