The answer is: [A]: "6" .
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Explanation:
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Using the Pythagorean theorem to solve for the hypotenuse of a right triangle:
a² + b² = c² ;
in which "c" is the length of the "hypotenuse" (for which we are to solve);
& "a" and "b" are the lengths of the other 2 (two) sides.
In this case, "a" and "b" are "equal lengths" ;
that is: a = b = 3√2 ;
So "(3√2)² + (3√2)² = c² " ; Solve for "c" ;
↔ c² = (3√2)² + (3√2)² ;
→ c² = 2*(3√2)² = 2 * (3²) * (√2)² ;
= 2 * 9 * 2 ;
= 18 * 2 = 36 ;
→ c² = 36 ;
Take the positive square root of each side of the equation ; to isolate "c" on one side of the equation ; & to solve for "c" (the length of the hypotenuse);
→ +√(c²) = +√36 ;
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→ c = 6 ; which is: "Answer choice: [A]: "6" .
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Function 1:
For the given table

you can plot the graph of the function (see first attached diagram). This function is linear and has equation f(x)=3x+4.
Function 2:
For the given function f(x)=-2x+3 you can create a table

and plot the graph (see second attached diagram).
Function 3:
For the given graph of the function, you can find the function:

Thus, the equation of the function 3 is 
The table will take a look

Answer:
Step-by-step explanation:
Total number of students = 68
Let history = H
Maths = M
English = E
n(H) = 25
n(M) = 25
n(E) = 34
n(HnMnE) = 3
Total = n(H) + n(M) + n(E) - people in exactly two groups + 2(people in exactly 3 groups) + people in none of the groups
68 = 25 + 25 + 34 - people in exactly two groups - 6 +0
68 = 84 -6 - people in exactly two groups
68 = 78 - people in exactly two groups
People in exactly two groups = 78 - 68
= 10
OR
From the venn diagram, people in exactly two groups are represented by x, y and z
Total = 25 - x - y - 3 + 25 - x - z - 3 + 34 - y - z - 3 + x + y + z + 3
68 = 50 - x - 3 + 34 - y - z - 3
68 = 84 - 6 - x - y - z
68 = 78 - x - y - z
68 - 78 = - x - y - z
-10 = -(x + y + z)
x+y+z = -10/-1
x+y+z = 10
The number of students that registered for exactly two courses = 10
Answer:
negative association
Step-by-step explanation:
Step-by-step explanation:
the quotient of a number and 3 is 6
Solution,
Let the number be x, then
