T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
Answer:
y = 6x + 22
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Slope Formula:
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-3, 14)
Point (-1, 16)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract/Add:
- Divide:
<u>Step 3: Find y-intercept </u><em><u>b</u></em>
- Define: y = 6x + b
- Substitute: 16 = 6(-1) + b
- Multiply: 16 = -6 + b
- Isolate <em>b</em>: 22 = b
- Rewrite: b = 22
<u>Step 4: Write linear equation</u>
y = 6x + 22
189/1000 would be the answer
9514 1404 393
Answer:
the scale drawing is larger
Step-by-step explanation:
The scale tells you that ...
17 cm on the scale drawing represent 1 mm on the actual object.
17 cm is larger than 1 mm, so the scale drawing is larger.
Answer:
$5308.79
Step-by-step explanation:
The future value can be computed from ...
FV = P(1 +r/n)^(nt)
where P is the principal invested, r is the annual interest rate, n is the number of times per year it is compounded, and t is the number of years.
Filling in the given numbers, we have ...
FV = $5000(1 +.03/12)^(12·2) ≈ $5308.79
Myron's withdrawal will be in the amount of $5308.79.