CL ≈ AE and HG≈ZR and ∠L≈∠E as both triangles are isosceles so CL=HL and AE=EZ
so HL≈AE≈ZR≈EZ so according to side angle side ΔCLH andΔ AZE both are congruent so side CH≈AZ
Answer:
Note that both relations and functions have domains and ranges. The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.
Answer: V 3
Step-by-step explanation:
If we firstly consider only the terms in x.
subtract 2x from both sides of the equation
⇒5+2x
−2x=2x−2x
+6
Observe that the x terms are eliminated and we are left with
5+0=0+6 that is 5=6 which is invalid
There is no solution to this equation.
<u>Given Function is</u>
- f ( x ) = 7x - 7 ------- eqn ( 1 )
<u>Now , put the value of x = 8 in eqn ( 1 )</u>
- f ( 8 ) = 7 ( 8 ) - 7
- f ( 8 ) = 56 - 7
- f ( 8 ) = 49 ------- eqn ( 2 )
<u>Now , put the value of x = 4 in eqn ( 1 )</u>
- f ( 4 ) = 7 ( 4 ) - 7
- f ( 4 ) = 28 - 7
- f ( 4 ) = 21 ------- eqn ( 3 )
<h3 />
<u>From eqn ( 2 ) nd eqn ( 3 ) we get,</u>
- f ( 8 ) + f ( 4 )
- 49 + 21
- 70
Hope Helps! :)
