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slavikrds [6]
3 years ago
8

I need help on this anyone

Mathematics
2 answers:
DanielleElmas [232]3 years ago
5 0

Perimeter = 2L + 2W

Perimeter = 2(4x^2) + 2(y^2)

Perimeter = 8x^2 + 2y^2

x^2 - 7x^2 = -6x^2

-3x - -2x = -3x +2x = -x

8 - -1 = 8+1 = 9

Answer = -6x^2 -x + 9

9x^2 -4x - 3x^2 -2x

9x^2 - 3x^2 = 6x^2

-4x - -2x = -4x +2x = -2x

Answer = 6x^2 -2x

Crank3 years ago
3 0

Answer:

A.

C.

A.

Step-by-step explanation:

Problem 1.

In a rectangle, opposite sides are congruent.

Two sides have length 4x^2 and two sides have length y^2.

perimeter = sum of the length of the sides

perimeter = 4x^2 + 4x^2 + y^2 + y^2

perimeter = 8x^2 + 2y^2

Choice A.

Problem 2.

(x^2 - 3x + 8) - (7x^2 - 2x - 1) =

Remove the first set of parentheses because they are not needed.

= x^2 - 3x + 8 - (7x^2 - 2x - 1) =

Think of the negative side tot eh left of the second set of parentheses as a -1 that needs to be distributed. Multiply each term inside the second set of parentheses by -1.

= x^2 - 3x + 8 -7x^2 + 2x + 1

Combine like terms.

= -6x^2 - x + 9

Choice C.

Problem 3.

You know the sum and one of the added terms. Subtract the known added term from the sum to find the other added term.

9x^2 - 4x - (3x^2 - 2x) =

As above, distribute teh negative sign by the second set of parentheses.

= 9x^2 - 4x - 3x^2 + 2x

= 6x^2 - 2x

Choice A.

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It is said that sufferers of a cold virus experience symptoms for 7 days. However, the amount of time is actually a normally dis
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Answer:

a) 0.18% of cold sufferers experience fewer than 4 days of symptoms

b) 64.40% of cold sufferers experience symptoms for between 7 and 10 days.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.2

a. What proportion of cold sufferers experience fewer than 4 days of symptoms?

This is the pvalue of Z when X = 4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 7.5}{1.2}

Z = -2.92

Z = -2.92 has a pvalue of 0.0018.

So 0.18% of cold sufferers experience fewer than 4 days of symptoms.

b. What proportion of cold sufferers experience symptoms for between 7 and 10 days?

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 7. So

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 7.5}{1.2}

Z = 2.08

Z = 2.08 has a pvalue of 0.9812.

X = 7

Z = \frac{X - \mu}{\sigma}

Z = \frac{7 - 7.5}{1.2}

Z = -0.42

Z = -0.42 has a pvalue of 0.3372.

So 0.9812 - 0.3372 = 0.644 = 64.40% of cold sufferers experience symptoms for between 7 and 10 days.

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To show the variation in a set of data, what do you calculate?
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