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4 years ago

The x-intercept of 2x + 3y = 12

Mathematics

1 answer:

andrezito [222]4 years ago

8 0

Answer:

That would be the 2( and not because of the the x ) it would actually be 2/3x because when u solve it the u should get or I'm guess you should get

y= 2/3x+4

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Help please and thank you

Lelu [443]

Answer: 30 posts

Step-by-step explanation:

each post is 5 feet apart and 30 x 2 + 45 x 2 = 150 which divided by 5 is 30

7 0

3 years ago

Hi can anyone help me solve the following problems with steps. Thank you! For 12 points. Adding and subtracting Fraction:

Yuliya22 [10]

Answer:

Q1 = $11\frac{2}{9}$

Q2 = $\frac{19}{24}$

Q3 = $1\frac{3}{7}$

Q4 = $2\frac{11}{12}$

Q5 = $\frac{11}{20}$ of the pizza is left

Step-by-step explanation:

Q1. $4\frac{4}{6} +7\frac{5}{9}$

Find Common Denominator

6 = 18

9 = 18

$4\frac{12}{18} +7\frac{10}{18}$

Then just add the whole numbers and numerators

$11\frac{22}{18}$ or $11\frac{4}{18}$

Simplify

$11\frac{2}{9}$

Q2. $2\frac{5}{8} -1\frac{5}{6}$

Find Common Denominator

8 = 24

6 = 24

$2\frac{15}{24} -1\frac{20}{24}$

Subtract by borrowing

$1\frac{39}{24} - 1\frac{20}{24}$

Then Subtract

$\frac{19}{24}$

Q3. $4-2\frac{4}{7}$

Convert

$3\frac{7}{7} -2\frac{4}{7}$

Then subtract

$1\frac{3}{7}$

Q4. $6\frac{1}{4} -3\frac{1}{3}$

Find Common Denominator

4 = 12

3 = 12

$6\frac{3}{12} -3\frac{4}{12}$

Borrow

$5\frac{15}{12} -3\frac{4}{12}$

Then Subtract

$2\frac{11}{12}$

Q5. Maria and Jane bought a whole pizza pie. Marie ate 1/5 of the pie and Jane ate 1/4 of the pie. Write a number sentence to find how much is left of the pie and solve it.

$\frac{1}{5} + \frac{1}{4}$

Find Common Denominator

5 = 20

4 = 20

$\frac{4}{20} +\frac{5}{20}$

Then add, after adding, subtract $\frac{9}{20}$ from the whole of the pizza.

$\frac{20}{20}-\frac{9}{20} = \frac{11}{20}$

Number Sentence:

$\frac{1}{5} + \frac{1}{4}=\frac{4}{20} +\frac{5}{20} = \frac{9}{20} \\= \frac{20}{20} -\frac{9}{20} = \frac{11}{20}$

8 0

2 years ago

A product code consists of four letters followed by five digits. Only the letters X, Y, and Z can be used ( and any of the digit

Morgarella [4.7K]

Answer:

$\frac{49}{81}$ , 60.494%

Step-by-step explanation:

I am going to try to tackle this. I might miss a step as I am currently taking discrete mathematics.

We want to find all the possibilities with 1y, 2ys, 3ys, and 4ys, out of all total possibilities.

_ _ _ _ _ _ _ _ _

For the letters, in each spot, we have 3 choices. For the numbers, we have 10 choices in each spot

3*3*3*3 * 10*10*10*10*10

= 81*100000

= 8100000

The number of Y's will never affect the number of permutations of the numbers.

So:

For 1 y, we have

Y _ _ _ * 10*10*10*10*10

But we also have

_ Y _ _

_ _ Y _

and

_ _ _ Y

So we can multiply the number we get in one calculation by 4

4 *

Y _ _ _ * 10*10*10*10*10

2*2*2 * 10*10*10*10*10

= 800000 * 4 = 3200000

For 2 y's, we have

YY _ _

_ YY _

__ YY

YY 2*2 * 10^5

4 * 100000

400000 * 3 = 1200000

For 3 y's, we have

YYY _

_ YYY

2 *

YYY 2 * 10^5

200000 * 2

= 400000

For 4 y's, we have

YYYY * 10^5

100000

Now we can add them all up and divide it by our original number 8100000

$\frac{100000 + 400000 + 1200000 + 3200000}{8100000} = \frac{49}{81}$

7 0

3 years ago

I'm really sick I got Covad-19and I really need help with 15 questions assignment and I'm really tired can't do anything right n

lesantik [10]

Can i see an image?? to help you better

8 0

3 years ago

Calculate the double integral. $$\iint_{R}{\color{red}4} xye^{x^{2}y}\hspace*{3pt}dA, \quad R = [0, 1] \times [0, {\color{red}7}

Lady_Fox [76]

Answer:

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

Step-by-step explanation:

Given that:

$\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7]$

The rectangle R = [0,1] × [0,7]

R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }

R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end {bmatrix}\ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = \dfrac{4}{2}[e^y -1]^7_0 \ dy$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-(e^0 -0)]$

$\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-1]$

$\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}$

3 0

4 years ago