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Nikitich [7]
4 years ago
15

What is square minus??​

Mathematics
1 answer:
julsineya [31]4 years ago
6 0

Answer:

Step-by-step explanation:

The square of minus 1 would be 1.

The square of minus 2 would be 4

The square of minus (-3) would be 9

And so on.

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Line segment AB has endpoints A (-4, 4) and B (2, 4). What is the length of line segment AB?
sineoko [7]

Step-by-step explanation:

the distance is sqrt ( (-6)^2 + (-12)^2) = sqrt(  36 + 144) = sqrt( 180) = sqrt(36*5) = 6 * sqrt(5)

2/(2+4) = 2/6 = 1/3

-2 + (1/3)*6*sqrt(5) = -2 + 2* sqrt(5)

6 + (1/3)*6*sqrt(5) = 6 + 2* sqrt(5)

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3 years ago
What is 6 1/6?? Plz help
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Improper fraction it would be 37/6
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Read 2 more answers
Graph -x^2+x+6=0 and state the consecutive integers between which roots are located
KengaRu [80]

Answer:

The roots of given quadratic equation lies from \begin{bmatrix}-2 , 3 \end{bmatrix}

Step-by-step explanation:

Given as :

The quadratic equation is x² - x -6 = 0

The quadratic equation is in form of ax² + bx +c = 0

Let x1 and x2 be the roots of equation

Sum of roots

So, x1 + x2 = \frac{-b}{a}  

And products of roots is x1 × x2 = \frac{c}{a}

So, x1 + x2 = \frac{1}{1}  

Or,   x1 + x2 = 1          ......A

And  x1 × x2 = \frac{-6}{1}

Or,  x1 × x2 = - 6

Now, (x1 - x2)² = (x1 + x2)²+ 4×x1×x2

Or,  (x1 - x2)² = (1)²+ 4×6

Or,  (x1 - x2)² = 25

So , x1 - x2 = \sqrt{25} = 5          ......B

Now solve eq A and eq B

Or, (x1 + x2) + (x1 - x2) = 1 +5

Or, 2 x1 = 6

∴   x1 = 3     And     x2 = - 2

Hence The roots of given quadratic equation lies from \begin{bmatrix}-2 , 3 \end{bmatrix}   Answer

6 0
4 years ago
A triangle has an area of 48 square centimeters. The height of the triangle is 6 centimeters. What is the base of the triangle?
andrew11 [14]

Question :-

  • A Triangle has an Area of 48 cm² . The Height of the Triangle is 6 cm . What is the Base of the Triangle ?

Answer :-

  • Base of Triangle is 16 cm .

Explanation :-

As per the provided information in the given question, we have been given that the Area of Triangle is 48 cm² . It's Height is given as 6 cm . And, we have been asked to calculate the Base of Triangle .

For calculating the Base of Triangle , we will use the Formula :-

\bigstar \:  \:  \:  \boxed{ \sf{ \: Area \: _{Triangle} \:  =  \:  \frac{1}{2} \:  \times  \: B \:  \times  \: H \:  }}

Where ,

  • B denotes to the Base .
  • H denotes to the Height .

Therefore , by Substituting the given values in the above Formula :-

\dag \: \: \: \sf { Area \: _{Triangle} \:  =  \:  \dfrac{1}{2} \:  \times  \: Base \:  \times  \: Height }

\longmapsto \: \: \: \sf {48 \: = \: \dfrac {1}{2} \: \times \: Base \: \times \: 6 }

\longmapsto \: \: \: \sf {48 \: \times \: 2 \: = \: 1 \: \times \: Base \: \times \: 6}

\longmapsto \: \: \: \sf {96 \: = \: 1 \: \times \: Base \: \times \: 6}

\longmapsto \: \: \: \sf {96 \: = \: 6 \: \times \: Base }

\longmapsto \: \: \: \sf {Base \: = \: \dfrac {96}{6} }

\longmapsto \: \: \: \textbf {\textsf {Base \: = \: 16 \: cm}}

Hence :-

  • Base of Triangle = 16 cm .

\underline {\rule {180pt} {4pt}}

6 0
2 years ago
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