So we know that there are 1000 mL in 1 L. We can set up an equation that allows us to solve for how many bottles are needed in order to empty the 30 L tank:

This equation then allows us to cancel out the units of mL and L, leaving us with how many bottles are needed per tank. Then we multiply straight across to give us:

The question asks us to round up to the next whole number, so
it would take 86 bottles to empty one 30 L tank.
If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
Answer:
208
Step-by-step explanation:
Given that;
Given that;
y= a(1 - b)^t
Where;
wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.
To obtain the constant b,
y= ae^-bt
Substituting values;
1000 = 3000 e^-b(50)
1000/3000 = e^b(50)
0.33 = e^b-(50)
ln (0.33) = ln(e^b(-50))
-1.1 = -50b
b= 1.1/50
b= 0.022
After two hours or 120 minutes;
y= 3000(1 - 0.022)^120
y= 207.8661772
y= 208
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