The equation of circle in standard form is 
<h3><u>Solution:</u></h3>
Given that circle having center point (3,7) and the radius r = 4
To find: equation of circle in standard form
<em><u>The equation of circle is given as:</u></em>

Where center (h,k) and radius r units
Given that center point (h , k) = (3, 7) and radius r = 4 units
Substituting the values in above equation of circle,

Thus the equation of circle in standard form is 
Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x =
.... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x =
.... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
=
+
,
x =
... And
squared is 11, making the area of this square 11 units².
Answer:
(9,4)
Step-by-step explanation:
Using the Midpoint theorem, we have
x=(10+8)/2=18/2=9
y=(4+4)/2=8/2=4