Answer:
P(Male or Type B) > P(Male | Type B)
Step-by-step explanation:
Total Female = 85 type A, 12 type B ⇒ 97 Female.
Total Male = 65 type A, 38 type B ⇒ 103 Male
Total type A = 65 + 85 = 150
Total type B = 12 + 38 = 50
total number of people = 97 + 103 = 200
Then the probability would be:
P(Male | Type B) = 
= 
= 0.368
P(Male or Type B) = 
= 
= 
= 
= 0.575
Hence, P(Male or Type B) > P(Male | Type B)
Male student: 40/100 = 2/5
graduate: 520/2106 = 65/252
2/5 + 65/252
= 829/1260 ( this is the probability)
Distributive property is
a(b+c)=ab+ac so
first, distribute
remember than (-) times (-)=(+)
-5(3x-8)=(-5)(3x)+(-5)(-8)=-15x+(+40)=-15x+40
so it is -15x+40=-45
the answe ris B
Find three consecutive odd integral such that the sum of seven times the smallest and twice the largest is -91
Answer:
The manager can select a team in 61425 ways.
Step-by-step explanation:
The order in which the cashiers and the kitchen crews are selected is not important. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
In how many ways can the manager select a team?
2 cashiers from a set of 10.
4 kitchen crews from a set of 15. So
The manager can select a team in 61425 ways.
