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3 years ago

What is the unit rate of this question

Mathematics

2 answers:

kykrilka [37]3 years ago

8 0

Answer: 64 mph

We can see that after every hour, the car has traveled 64 miles. So the speed rate is 64 miles per hour.

Inessa [10]3 years ago

3 0

Answer:

64 miles per hour

Step-by-step explanation:

The graph passes through the origin thus the quantities are in proportion.

The unit rate ( speed ) is the distance travelled in 1 hour.

From the graph the distance travelled in 1 hour is 64 miles

unit rate = 64 mph

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A-t shirt cost $4 a sweter cost 4 times as much as the t-s

slava [35]

T-shirt costs $4
Sweater costs $4(4)

Sweater costs 4 x 4

4 x 4 = 16

Sweater costs $16

hope this helps

5 0

4 years ago

Read 2 more answers

Write the equation of the parabola that has the vertex at point (− 1/2 ,2.3) and passes through the point (5,2 3/4 ).

Alex73 [517]

Answer:

The equation of parabola in vertex form is $y=0.015(x+0.5)^2+2.3$

Step-by-step explanation:

Given coordinate of vertex is $(-\frac{1}{2},2.3)$ and the parabola passes through the point $(5,2\frac{3}{4})$

So, the equation of parabola in vertex form is

$y=a(x-h)^2+k$

Where $(h,k)$ is the coordinate of the vertex.

$(h,k)=(-\frac{1}{2},2.3)=(-0.5,2.3).\\\\So,\ h=-0.5\ and\ k=2.3$

Plugging these value in equation we get,

$y=a(x-(-0.5))^2+2.3\\\\y=a(x+0.5)^2+2.3$

Now, we will find the value of $a$

Plug the coordinate $(5,2\frac{3}{4})$

$(x,y)= (5,2\frac{3}{4})\\\\(x,y)=(5,\frac{11}{4})\\\\(x,y)=(5,2.75)$

$2.75=a(5-(-0.5))^2+2.3\\\\2.75=a(5+(0.5))^2+2.3\\\\2.75=a(5.5)^2+2.3\\\\2.75=a\times30.25+2.3\\\\2.75-2.3=a\times30.25\\\\0.45=a\times30.25\\\\\frac{0.45}{30.25}=a\\ \\a=0.0149$

Plug the value of $a$ in the equation $y=a(x+0.5)^2+2.3$

So, the equation of parabola with vertex $(-\frac{1}{2},2.3)$ and passes through the point $(5,2\frac{3}{4})$ is

$y=0.0149(x+0.5)^2+2.3$ ≅ $y=0.015(x+0.5)^2+2.3$

5 0

3 years ago

Pls HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!! :))

artcher [175]

Answer:

the fourth one

8 0

3 years ago

Read 2 more answers

Find the equation in standard form of the line with slope

Serhud [2]

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 5}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{7}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-7=\cfrac{7}{2}(x-5)\implies y-7=\cfrac{7}{2}x-\cfrac{35}{2}
\\\\\\
y=\cfrac{7}{2}x-\cfrac{35}{2}+7\implies \stackrel{standard~form}{-\cfrac{7}{2}x+y=-\cfrac{21}{2}}$

3 0

3 years ago

Can you please simplify (x^2)^5 ?

Sloan [31]

(x^2)^5 = x^(2*5) = x^10

8 0

3 years ago