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3 years ago

What is the unit rate of this question

Mathematics

2 answers:

kykrilka [37]3 years ago

8 0

Answer: 64 mph

We can see that after every hour, the car has traveled 64 miles. So the speed rate is 64 miles per hour.

Inessa [10]3 years ago

3 0

Answer:

64 miles per hour

Step-by-step explanation:

The graph passes through the origin thus the quantities are in proportion.

The unit rate ( speed ) is the distance travelled in 1 hour.

From the graph the distance travelled in 1 hour is 64 miles

unit rate = 64 mph

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In the figure below, AD is the perpendicular bisector of CB. Based on this information, which other statement can be proven to b

snow_tiger [21]

Answer:

463833

expand

Medium

Solution

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In △ABD and △ACD, we have

DB=DC ∣ Given

∠ADB=∠ADC ∣ since AD⊥BC

AD=AD ∣ Common

∴ by SAS criterion of congruence, we have.

△ABD≅△ACD

⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal

Hence, △ ABC is isosceles.

5 0

2 years ago

Read 2 more answers

Does anyone know this?

Veseljchak [2.6K]

Answer:

option number a -4 and -9

7 0

3 years ago

In two or more complete sentences, explain whether the sequence is finite or infinite. Describe the pattern in the sequence if i

levacccp [35]

The sequence is given as follow
$3a$ , $3 a^{2}b,3 a^{3} b^{2} , 3 a^{4} b^{3}$

When finding the pattern of a sequence, we can try to work out whether there is a common difference or a common ratio between each term. We try by finding a common ratio

$\frac{3 a^{2}b }{3a} =ab$
$\frac{3 a^{3 b^{2} } }{3 a^{2}b }=ab$
$\frac{3 a^{4} b^{3} }{3 a^{3} b^{2} }=ab$

The term to term rule is multiplied by $ab$

The $5^{th}$ term is given $3 a ^{4} b^{3}$ × $ab=3 a^{5} b^{4}$

The $6^{th}$ term is given by $3 a^{5} b^{4}$ × $ab=3 a^{6} b^{5}$

8 0

3 years ago

Use the zero product property to find the solutions to the equation x^2-15x-100=0

Helen [10]

Answer:

It’s c

Step-by-step explanation:

5 0

3 years ago

110 decreased by 70%

Bess [88]

110x0.7= 77
110-77= 33
so 33 is your answer

7 0

2 years ago