Answer: see below
<u>Step-by-step explanation:</u>
I'm not sure exactly what you are asking for but here is what the box plot tells you:
Minimum is 17 items.
Q1 (Lower Quartile) is 22 items. So, 25% of the customers bought 22 items.
Q2 (Median) is 32 items. So, 50% of the customers bought 32 items.
Q3 (Upper Quartile) is 35 items, So, 75% of the customers bought 35 items.
Maximum is 62 items.
The data is "heavier" on the right so it is skewed left.
Range is 62 - 17 = 45
IQR (Interquartile range) is Q3 - Q1 = 35 - 22 = 13
Step 1
<span>Calculate the error
</span>error=75-64-----> 11 ft
step 2
<span>Divide the error by the exact value
</span>11/64=0.1719
step 3
<span>Convert that to a percentage
</span>0.1719*100=17.19%
the answer is
17.19%
We can start by setting out what we know simply.
Cow produces 5 liters a day.
The cow can make 200% more.
200% of 5, is 10.
If he makes 200% more, he will make 10 liters more.
He already makes 5.
10+5 is what he will make.
FINAL ANSWER:
<em>"If the cow's diet is improved, the cow will produce 15 liters of milk in a day."</em>
6
(2x+8) -> (2(5)+8)-> 18
18/3 is 6
