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Brums [2.3K]
3 years ago
15

What is equivalent to 4 square root 5

Mathematics
2 answers:
Grace [21]3 years ago
4 0
2√20 and 4*5^1/2. Explanation Below:
---
When we simplify 2√20, we get 4√5, and 5^1/2 is √5. Therefore, 4*5^1/2 is 4√5.
---
Hope this helps!
professor190 [17]3 years ago
4 0

Answer:

Option 1,3 and 4.

Step-by-step explanation:

Given : Expression 4 square root 5 i.e. 4\sqrt{5}

To find : What is equivalent to 4\sqrt{5}?

Solution :

We solve the given options to get the expression,

1) 2\sqrt{20}

We can re-write as,

2\sqrt{20}=2\sqrt{4\times 5}=4\sqrt 5  

2) 6^{\frac{1}{2}}-5^{\frac{1}{2}}

We can re-write as,

6^{\frac{1}{2}}-5^{\frac{1}{2}}=\sqrt{6}-\sqrt{5}            

3) 3\times5^{\frac{1}{2}+5^{\frac{1}{2}

We can re-write as,

3\times5^{\frac{1}{2}+5^{\frac{1}{2}=3\sqrt{5}+\sqrt5=\sqrt 5(3+1)=4\sqrt{5}  

4) 4\times 5^{\frac{1}{2}}

We can re-write as,

4\times 5^{\frac{1}{2}}=4\sqrt{5}  

5) 2\sqrt{10}

We can re-write as,

2\sqrt{10}=2\sqrt{2\times 5}

6) 3\times 5^{\frac{1}{2}}

We can re-write as,

3\times 5^{\frac{1}{2}}=3\sqrt{5}  

Therefore, From the following options the equivalent are option 1,3 and 4.

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PLS HELP
Anika [276]

The chairs in the auditorium illustrates an arithmetic sequence

  • The recursive rule is:  an = an-1 + 8; a1 = 26
  • The explicit rule is:  an = 18 + 8n
  • There are 74 seats in the 7th row
  • 840 chairs can fit the auditorium

<h3>The recursive rule</h3>

From the question, we have the following sequence:

Seats: 18, 26, 34

Rewrite as:

26 = 18 + 8

34 = 26 + 8

The above means that:

The number of seats on a row is 8 added to the the number of seats on the previous row.

Hence, the recursive rule is:

an = an-1 + 8; a1 = 26

<h3>The explicit rule</h3>

In (a), we have:

a1 = 26 and d = 8

The explicit rule is calculated using:

an = a1 + (n -1) * d

This gives

an = 26 + (n - 1) * 8

Expand

an = 26 - 8 + 8n

Evaluate the difference

an = 18 + 8n

Hence, the explicit rule is:

an = 18 + 8n

<h3>The number of seats in the row 7</h3>

This means that n = 7.

So, we  have:

a7 = 18 + 8 * 7 = 74

Hence, there are 74 seats in the 7th row

<h3>The sigma notation</h3>

We have the maximum number of rows to be 12.

So, the sigma notation would be:

\sum\limits^{12}_{n=1} {18 + 8n}

The total number of seats is:

Sn = n/2(2a + (n -1) * d)

This gives

S12 = 12/2(2 * 26 + (12 -1) * 8)

S12 = 840

Hence, 840 chairs can fit the auditorium

Read more about arithmetic sequence at:

brainly.com/question/6561461

7 0
2 years ago
If f[6} = x ^ -2x , find: f [6} =
ASHA 777 [7]

Answer:

1/ 6^12

Step-by-step explanation:

f[x} = x ^ (-2x)

f(6) = 6 ^ (-2*6)

      = 6 ^ -12

   We know the negative exponent moves it to the denominator

     = 1/ 6^12

7 0
3 years ago
A rectangular turtle aquarium is 6 ft long by 4 ft wide. The aquarium is enlarged by increasing
My name is Ann [436]

Answer:

8ft x 6ft

Step-by-step explanation:

For this problem, we want to create measurements of length and width that double our current area.  First we need to find the current area.

C_Length = 6 ft

C_Width = 4 ft

C_Area = C_Length * C_Width

C_Area = 6 ft * 4 ft = 24 ft^2

Now we want our new area to be double the old area.

N_Area = 2C_Area

N_Area = 2 * 24 ft^2

N_Area = 48 ft^2

Now we simply need to find the increase in width and length, distributed equally, that will create the new area.

N_Area = (C_Length + x) * (C_Width + x)

Where x is the amount that each variable is increased by to create the new area.

Now we simply solve for x.

N_Area = (C_Length + x) * (C_Width + x)

48 = (6 + x) * (4 + x)

48 = 24 + 10x + x^2

0 = -24 + 10x + x^2

Now we can either apply the quadratic formula or attempt to factor using the constant break down method.

(x + 12) (x - 2) = 0

x = -12; x = 2

Note that we will choose x = 2 since the other option would require us to have negative material, which is impossible.

Now we can check to validate our answer by plugging in the value of x.

48 ?= (6 + 2) * (4 + 2)

48 ?= (8) * (6)

48 == 48

Thus, we have found the dimensions of the new aquarium, 8ft x 6ft.

Cheers.

6 0
3 years ago
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