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Brums [2.3K]
3 years ago
15

What is equivalent to 4 square root 5

Mathematics
2 answers:
Grace [21]3 years ago
4 0
2√20 and 4*5^1/2. Explanation Below:
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When we simplify 2√20, we get 4√5, and 5^1/2 is √5. Therefore, 4*5^1/2 is 4√5.
---
Hope this helps!
professor190 [17]3 years ago
4 0

Answer:

Option 1,3 and 4.

Step-by-step explanation:

Given : Expression 4 square root 5 i.e. 4\sqrt{5}

To find : What is equivalent to 4\sqrt{5}?

Solution :

We solve the given options to get the expression,

1) 2\sqrt{20}

We can re-write as,

2\sqrt{20}=2\sqrt{4\times 5}=4\sqrt 5  

2) 6^{\frac{1}{2}}-5^{\frac{1}{2}}

We can re-write as,

6^{\frac{1}{2}}-5^{\frac{1}{2}}=\sqrt{6}-\sqrt{5}            

3) 3\times5^{\frac{1}{2}+5^{\frac{1}{2}

We can re-write as,

3\times5^{\frac{1}{2}+5^{\frac{1}{2}=3\sqrt{5}+\sqrt5=\sqrt 5(3+1)=4\sqrt{5}  

4) 4\times 5^{\frac{1}{2}}

We can re-write as,

4\times 5^{\frac{1}{2}}=4\sqrt{5}  

5) 2\sqrt{10}

We can re-write as,

2\sqrt{10}=2\sqrt{2\times 5}

6) 3\times 5^{\frac{1}{2}}

We can re-write as,

3\times 5^{\frac{1}{2}}=3\sqrt{5}  

Therefore, From the following options the equivalent are option 1,3 and 4.

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The length of a rectangle is 1 ft less than twice the width, the area of the rectangle is 21 ft squared. What’s the length
guapka [62]

Answer:

The length of the rectangle is 6 feet

Step-by-step explanation:

Given as :

The length of rectangle is 1 feet less than twice the width

So, let The width of rectangle = w feet

The length of rectangle = ( 2 w - 1 )  feet

The area of the rectangle = 21 feet²

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Or, 21 feet² =  ( 2 w - 1 ) feet × w feet

or, 21 = 2 w² - w

or, 2 w² - w - 21 = 0

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here we consider only positive value of w i.e  \frac{7}{2} feet

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3 0
3 years ago
I need to answer for the parentheses
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3 years ago
(SAT Prep) Find the value of x.<br> X<br> 125°<br> 115°
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<h3>Answer : 60°</h3>

<h3>Way to do </h3>

#look pic for detailed info

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180° - 60° = 120°

180° - 120° = 60°

3 0
3 years ago
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