Answer:
Class 8 has 27 and class 7 has 40
Step-by-step explanation:
8th (r) class has 13 fewer than 7th (x).
x -13 = r
Total for both classes = 67
r + x - 13 = 67
r + x = 80
80 divided by two = 40 (per class)
40 - 13 = 27
Answer:
m=
Step-by-step explanation:
10•4=40. 40 is the perimeter of the square. To find the perimeter of the semicircle use the circle perimeter (circumference) formula and divide that answer by two. This would be pi•10. You get 31.4. Then divide by 2 so it’s 15.7. Finally add 15.7 and 40. Hope this helps... sorry it’s such a long answer
∆ABC=∆DEF
AB=DE –>String
BC=EF–> Rib
m<C=m<F=90° –>List
AC=DF
So m<A=m<D=35 (It is not clear whether the number is 35 or 36, but the same number)
Answer:
y= -7
Step-by-step explanation:
So first distribute the 8
4=8y+32-4y
now combine like terms (the -4y+8y)
4=32+4y
Subtract 32 on both sides to isolate 4y
-28=4y
now divide 4 on both sides to isolate Y
-7=y
so y= -7