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4 years ago

This right square pyramid has a base length of 4 inches and a slant height of 7 inches what is the surface area of this pyramid?

Mathematics

1 answer:

Vesnalui [34]4 years ago

7 0

Answer:

Right Regular Pyramid Surface Area = (½ * Perimeter of Base * Slant Height)

Perimeter of Base = 16 inches

Right Regular Pyramid Surface Area = (½ * 16 * 7)

= 56 square inches

Step-by-step explanation:

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Triangle ABC

Stolb23 [73]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's solve for value of values of x and y ~

According to Angle sum property of triangles :

$\qquad \sf \dashrightarrow \: 70 \degree + 58\degree + x = 180\degree$

$\qquad \sf \dashrightarrow \: x\degree + 128\degree = 180\degree$

$\qquad \sf \dashrightarrow \:x = 180\degree - 128\degree$

$\qquad \sf \dashrightarrow \: x = 52\degree$

Now, solve for y ~

$\qquad \sf \dashrightarrow \: 70\degree + 49\degree + y = 180\degree$

$\qquad \sf \dashrightarrow \: y + 119 = 180\degree$

$\qquad \sf \dashrightarrow \: y = 180 - 119\degree$

$\qquad \sf \dashrightarrow \: y = 61 \degree$

Now, by the results we got, we can conclude that :

The two triangles are not similar because 70 + 58 + x = 180 means x = 52° and 70 + 49 + y=180 means y = 61°

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