Hello XD
3(x+2) = 3x+6
Distributive property
(3)(x)+(3)(2) = 3x+6
3x+ 6 = 3x+6
Now subtract 3x from both sides
3x+6-3x = 3x+6-3x
6=6
Subtract 6 from both sides
6-6 = 6-6
0=0
In this case the answer is : All real numbers are solution
Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}
The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go
{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers
6/10
.6
If i'm wrong, sorry, haven't done this kind of stuff in a while
Answer:-0
Step-by-step explanation:
Let x, x+1,x+2, x +3 are the <span>numbers
so
</span>x + x +1 + x +2 +x +3 = 198
4x + 6 = 198
4x =198-6
4x = 192
x = 192/4
x = 48
x + 1 = 48 + 1 = 49
x + 2 = 48 + 2 = 50
x + 3 = 48 + 3 = 51
proof
48 + 49 + 50 + 51 = 198
so the numbers are 48, 49, 50, 51
fourth number in this sequence is 51
