<span>the tens digit = n
</span><span>the units digit = n-5
n + n-5 = 9
2n = 9+5
2n = 14
n = 7 </span>← the tens digit
the units digit = n-5 = 7 - 5 = 2
<span>the number is 72</span>
You answer is B because supplementary is 180°
Answer:
Step-by-step explanation:
<u>Take any two points or coordinated from the graph.</u>
Let's take (2,2) and (0,-3)
So,
Hence,
![\sf Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\\\Slope = \frac{-3-2}{0-2} \\\\Slope = \frac{-5}{-2} \\\\Slope = \frac{5}{2} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20Slope%20%3D%20%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D%20%20%5C%5C%5C%5CSlope%20%3D%20%5Cfrac%7B-3-2%7D%7B0-2%7D%20%5C%5C%5C%5CSlope%20%3D%20%5Cfrac%7B-5%7D%7B-2%7D%20%5C%5C%5C%5CSlope%20%3D%20%5Cfrac%7B5%7D%7B2%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
4
Step-by-step explanation:
The degree of a polynomial is the highest of the degrees of the polynomial's monomials with non-zero coefficients
In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.
In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.
Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
