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Nesterboy [21]
3 years ago
13

Can you simplify 3(x+2) = 3x+6 in distributive property

Mathematics
2 answers:
Vanyuwa [196]3 years ago
3 0

Hello XD

3(x+2) = 3x+6

Distributive property

(3)(x)+(3)(2) = 3x+6

3x+ 6 = 3x+6

Now subtract 3x from both sides

3x+6-3x = 3x+6-3x

6=6

Subtract 6 from both sides

6-6 = 6-6

0=0

In this case the answer is : All real numbers are solution

tankabanditka [31]3 years ago
3 0
Ok so

remember the distributive property

a(b+c)=ab+ac

so
3(x+2)=3x+6
we have
3x+6=3x+6
identical
now watch
minus 3x both sides
6=6
true staement

therefor any number you put for x will work

answer is all real numbers
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How do you find the product of -2(3.1)
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2 years ago
The sum of squares of two consecutive positive even integers is 52 more than their product. Find these numbers.
natulia [17]

Answer:

The first set of consecutive even integers equals (8 , 6)

The second set is ( - 8 and - 6) which also works.

Step-by-step explanation:

Equation

(x)^2 + (x + 2)^2 = (x)(x + 2) + 52            Remove the brackets on both sides

Solution

x^2 + x^2 + 4x + 4 = x^2 + 2x + 52        Collect the like terms on the left

2x^2+ 4x+ 4 = x^2 + 2x + 52                  Subtract right side from left

2x^2 - x^2 + 4x - 2x + 4 - 52  =  0          Collect the like terms

x^2 + 2x - 48 = 0                                     Factor

(x + 8)(x - 6) = 0

Answer

Try the one you know works.

x - 6 = 0

x = 6

Therefore the two integers are 6 and 8

6^2 + 8^2 = 100

6*8 + 52  = 100

So 6 and 8 is one set of  consecutive even numbers that works.    

========================

What about the other set.

x + 8 = 0

x = - 8

x and x + 2

- 8  and -8 + 2 = - 8, - 6

(- 8 )^2 + (- 6)^2 = 100

(-8)(-6) + 52 = 100

Both sets of consecutive numbers work.


5 0
3 years ago
Read 2 more answers
I dont understand quadratic equations
Yanka [14]
At least you must give a question that goes beyond your understanding?
6 0
3 years ago
Read 2 more answers
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