If 2 straight lines intersect as shown, what is the value of z
1 answer:
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To solve this first we need to get are chunk which is already solved for here as
Y=(4x) so one the chunk side of this we dont have to solve for it, so now we can just skip right to solving this equation like so. First input the numbers x+(4x)=5,
Distribute/Combine like terms in this case
5x=5
Divide by 5
x=1
So now that we have x we can plug it into are chunk and then we have are answer
Y=(4x)
Y=(4*1)
Y=4
So are end answers are
Enjoy!=)
Y=(4x) so one the chunk side of this we dont have to solve for it, so now we can just skip right to solving this equation like so. First input the numbers x+(4x)=5,
Distribute/Combine like terms in this case
5x=5
Divide by 5
x=1
So now that we have x we can plug it into are chunk and then we have are answer
Y=(4x)
Y=(4*1)
Y=4
So are end answers are
Enjoy!=)
Answer:
- QN = 3√7
- OI = √7
Step-by-step explanation:
The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...
DQ = (3 units)·3 = 9 units
KO = (3 units)·1 = 3 units
Then the base lengths QN and OI can be found from the Pythagorean theorem:
KI² = KO² +OI²
4² = 3² +OI²
OI = √(16 -9)
OI = √7
QN = 3·OI = 3√7
<h2><u>Question</u>:-</h2>
Find the volume of a cylinder with a radius of 3 meters and a height of 13 meters.
<h2><u>Answer</u>:-</h2><h3>Given:-</h3> Radius (r) of a cylinder = 3 meters.
Height (h) of a cylinder = 13 meters.
The volume of a cylinder.
<h2>Solution:-</h2>We know,
Formula of Volume of a cylinder is πr²h.
So, Volume of a cylinder = 3.14 × (3)² × 13
Volume of a cylinder = 3.14 × 3 × 3 × 13
Volume of a cylinder = 367.38 cubic meters.
<h3>The volume of a cylinder is <u>3</u><u>6</u><u>7</u><u>.</u><u>3</u><u>8</u><u> </u><u>cubic </u><u>meters</u>. [Answer]</h3>