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2 years ago

What is the order of these numbers from least to greatest 1 4/5, 1/2, -3 7/8, -7/9, -3/5

Mathematics

1 answer:

maksim [4K]2 years ago

4 0

Answer:

-3 7/8, -7/9, -3/5, 1/2, 1 4/5

Step-by-step explanation:

You could also change it to a decimal if that makes it easier.

-3 7/8 = -3.875

-7/9 = -0.778

-3/5 = -0.6

1/2 = 0.5

1 4/5 = 1.8

In order from least to greatest, that'd be -3.875, -0.778, -0.6, 0.5, 1.8

After that, all you gotta do is change them back into a fraction.

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Solve for z? 2x-4y+4z-6w=4 6w-4x+4y-4z=-12 6w+4x-2y+6z=64 4z+2w+6y-4x=56

NikAS [45]

Answer:

z ≈ 9.22

Step-by-step explanation:

Given the equations

2x-4y+4z-6w=4 ................ 1

6w-4x+4y-4z=-12 ...............2

6w+4x-2y+6z=64 ............... 3

4z+2w+6y-4x=56 ................ 4

We will first need to reduce the equation by cancelling out some variables.

Add equations 1 and 2 will give;

(2x-4x)+(-4y+4y)+(4z-4z)+ (-6w+6w) = 4+12

-2x +0 = 16

-2x = 16

x = -8

Also, equation 2 minus 3

6w-6w+(-4x-4x)+4y+2y+(-4z-6z) = 12-64

-8x+6y-10z = -52

-8(-8)+6y-10z = -52

64+6y-10z = -52

6y-10z = -52-64

6y-10z = -116

3y-5z = -58 ... 5

Equation 3 * 1 and eqn 4 * 3

6w+4x-2y+6z=64 ............... 3

4z+2w+6y-4x=56 ................ 4

6w+4x-2y+6z=64

12z+6w+18y-12x= 168

Subtracting both equations;

16x-20y-6z = -104

8x-10y-3z = -52

8(-8)-10y-3z = -52

-64-10y-3z = -52

-10y-3z = -52+64

-10y-3z = 12 ....... 6

equating 5 and 6 and solving simultaneously;

3y-5z = -58 ... 5 * 10

-10y-3z = 12 ....... 6 * 3

30y-50z = -580

-30y-9z = 36

Add both equations

-50z-9z = -580+36

-59z = -544

z = -544/-59

z = 9.22

Hence z ≈ 9.22

4 0

2 years ago

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

uysha [10]

Answer:

The perimeter of the trapezoid is $38.25\ units$

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

In this problem

$P=QR+RS+ST+QT$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$Q(8, 8), R(14, 16), S(20, 16),T(22, 8)$

step 1

Find the distance QR

$Q(8, 8), R(14, 16)$

substitute the values in the formula

$d=\sqrt{(16-8)^{2}+(14-8)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$QR=10\ units$

step 2

Find the distance RS

$R(14, 16), S(20, 16)$

substitute the values in the formula

$d=\sqrt{(16-16)^{2}+(20-14)^{2}}$

$d=\sqrt{(0)^{2}+(6)^{2}}$

$d=\sqrt{36}$

$RS=6\ units$

step 3

Find the distance ST

$S(20, 16),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-16)^{2}+(22-20)^{2}}$

$d=\sqrt{(-8)^{2}+(2)^{2}}$

$d=\sqrt{68}$

$ST=8.25\ units$

step 4

Find the distance QT

$Q(8, 8),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-8)^{2}+(22-8)^{2}}$

$d=\sqrt{(0)^{2}+(14)^{2}}$

$d=\sqrt{196}$

$QT=14\ units$

step 5

Find the perimeter

$P=10+6+8.25+14=38.25\ units$

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3 years ago

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Zielflug [23.3K]

First solve for the other angles.
You know one angle is 15º.
The one across from it is also 15º since it is a vertical angle to the known 15º angle.
Both of those together gets 30º.
The whole thing is 360º, so just subtract 30 from 360 and divide.
360 - 30 = 330
Do the same for the 15x angle.
The one under/across to it is a vertical angle so is also 15xº.
Now you are left with 30xº = 330.
Just divide now.
330 / 30 = 11
x = 11
15x = 165

Checking your work:
15x = 165
15x = 165
15
15
Those are the angles.
Add those numbers together and make sure it adds up to 360º.
165 + 165 + 15 + 15 = 360
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7 0

2 years ago

What is the value of x in the equation 2x - 3 = 9- 4x? o 6 o 3 O 1 02

riadik2000 [5.3K]

Answer:

2? The last one

Step-by-step explanation:

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2 years ago

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Whatas the nth term of the geometric sequence 4,8,16,32

GenaCL600 [577]