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3 years ago

Whoever answers right first gets brainliest. :)

1 answer:

5 0

Hi there! There are no numbers listed, therefore I'm unable to do answer your question. Are there numbers included in the problem?

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How do I subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 ?

SVETLANKA909090 [29]

$-2m^2+4mn-6n^2$

1) Let's write out both expressions subtracting 4m²+2mn+8n² from 2m²+6mn+2n²

$\begin{gathered} 2m^{2}+6mn+2n^{2}-(4m^{2}+2mn+8n^2)_{} \\ 2m^2+6mn+2n^2-4m^2-2mn-8n^2 \\ -2m^2+4mn-6n^2 \end{gathered}$

2) Note that when we subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 we need to swap the sign by placing -1 outside the parentheses and then combine like terms adding those terms algebraically.

4 0

1 year ago

What is a factor (ﾉ◕ヮ◕)ﾉ I'm dumbヽ(◕ヮ◕ヽ)

Minchanka [31]

it’s basically just any number that can be multiplied with another to get a new expression

3 0

3 years ago

Read 2 more answers

Ted likes to run long distances. He can run 20 km in 95 minutes. He wants to know how many kilometers he will go if he runs at t

kykrilka [37]

Answer: 60 Km

Step-by-step explanation: Because if you divied 95*285= 3 so you know that it will take him 3 times the amount has given to us so we just have to do 3* 20 km which is 60

-Alissa

Hope i helped sorry if this is wrong it makes sense to me but then again i am not the best at math sooo..... sorry if this is wrong but i am pretty sure it is right :/

4 0

3 years ago

Read 2 more answers

Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park. Max's family spent $146 on 3 adults tic

Firdavs [7]

The price of 1 youth ticket is $ 22

Solution:

Let "y" be the price of 1 youth ticket

Let "a" be the price of 1 adult ticket

To find: price of 1 youth ticket

Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park

So we can frame a equation as:

2 adult tickets x price of 1 adult ticket + 3 youth tickets x price of 1 youth ticket = 134

$2 \times a + 3 \times y = 134$

2a + 3y = 134 ---- eqn 1

Max's family spent $146 on 3 adults tickets and 2 youth tickets

So we can frame a equation as:

3 adult tickets x price of 1 adult ticket + 2 youth tickets x price of 1 youth ticket = 146

$3 \times a + 2 \times y = 146$

3a + 2y = 146 ----- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "y"

Multiply eqn 1 by 3

6a + 9y = 402 ---- eqn 3

Multiply eqn 2 by 2

6a + 4y = 292 ----- eqn 4

Subtract eqn 4 from eqn 3

6a + 9y = 402

6a + 4y = 292

( - ) -------------------

5y = 110

y = 22

Thus the price of 1 youth ticket is $ 22

3 0

3 years ago

Prove: An odd number squared is an odd number. = (2n + 1)2

Mnenie [13.5K]

Answer:

${(2n + 1)}^{2} = 4 {n}^{2} + 4n + 1 = 2(2 {n}^{2} + 2n) + 1$

4 0

2 years ago