Bill used 3/8 cup of raisins and 2/3 cup of banana chips to make a snack. Which statement correctly compares the fractions

Find the length of each segment. SEE EXAMPLES 1 AND 2

wlad13 [49]

The lengths of the line segments are summarized in the following list:

DF = 3
DE = 8 / 3
FG = 3
FH = 9 / 2
GH = 3 / 2
EH = - 11 / 6

<h3>How to calculate the length of a line segment based on point set on a number line</h3>

Herein we have a number line with five points whose locations are known. The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:

DF = - 1 - (- 4)

DF = 3

DE = (- 1 - 1 / 3) - (- 4)

DE = 3 - 1 / 3

DE = 8 / 3

FG = 2 - (- 1)

FG = 3

FH = (3 + 1 / 2) - (- 1)

FH = 4 + 1 / 2

FH = 9 / 2

GH = (3 + 1 / 2) - 2

GH = 1 + 1 / 2

GH = 3 / 2

EH = (3 + 1 / 2) + (- 1 - 1 / 3)

EH = - 2 + (1 / 2 - 1 / 3)

EH = - 2 + 1 / 6

EH = - 11 / 6

To learn more on lengths: brainly.com/question/8552546

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7 0

1 year ago

What is the center of the circle x2 + y2 - 13x – 22 =0

Hatshy [7]

$\frac{13}{2} 0$

$\frac{ \sqrt{257} }{2}$

6 0

3 years ago

Read 2 more answers

Helppp meee pleaseeee

podryga [215]

The correct answer is D

4 0

3 years ago

Read 2 more answers

If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye

True [87]

First off, see how much 8700 as principal, yields at 3% APR
that is $\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}$

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}
\\\\\\
\implies \boxed{?}\\\\
-----------------------------\\\\
\textit{how much to invest at 6\%?}
\\\\\\
$

$\bf \qquad \textit{Simple Interest Earned}\\\\
(393-\boxed{?}) = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &1
\end{cases}
\\\\\\
\textit{solve for "P", to see how much should the Principal be}\\\\
\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}$

6 0

3 years ago

The Millers plan on retiring soon. When they were first married they purchased 1,000 shares in a mutual fund that was at that ti

kozerog [31]

Answer: There is 680% increase for the fund.

Step-by-step explanation:

Since we have given that

Number of shares they purchased = 1000

Cost of per share at the time of their marriage = $10

So, Amount of fund will be

$1000\times 10=\$10000$