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3 years ago

X + -4 =11 marking brainliest show work too please

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

move the -4 to the other side

X = 11 + 4

X = 15

mr_godi [17]3 years ago

5 0

Answer:

X=15

Step-by-step explanation:

Change X+-4 to X-4=11

Add 4 and you get

X=15

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Write 9 as a power of the base 3

malfutka [58]

9 = 3^2
Since 3 squared equals 9, that is how 9 as a power of the base 3 should be written.

4 0

2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

2 years ago

Read 2 more answers

3(2x) + 3(-1) = -21 <br><br>6x - 3 = -21<br> What property is being used ?

kaheart [24]

Distributive property, since 3(2x) you distribute and get 6x

4 0

3 years ago

How do you write a improper fraction a mixed number if it's a negative

Nookie1986 [14]

You simply do it the same way as a positive number, just with a negative sign in front :)

8 0

3 years ago

What is the y-coordinate of the point that divides the directed

e-lub [12.9K]

Answer:

(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

The line segment that divides the segment from J to K in any given ratio can be determined using the formula.

$P(x,y)=\left(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n}\right)$

In the given case:

$(x_1,y_1)=(-3,1), (x_2,y_2)=(8,11)$ , m:n=2:3

Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:

$\dfrac{my_2+ny_1}{m+n}=\dfrac{2*11+3*1}{3+2}\\\\=\dfrac{22+3}{5}\\\\=\dfrac{25}{5}\\\\=5$

The y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.

3 0

2 years ago