The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!
Choice B (4, -2)

2 is not greater than or equal to 6, so choice B doesn't work.
Choice C (4, 2)

Since 6 is equal to 6 and 4 is equal to 4, choice C works!
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Answer: C) (4, 2)
Since we have two points (2,54) and (4,54), we can assume a linear function and solve for the slope and intercept. So if V=kt+b where t is time passed and v is velocity of the car, we can plug in and solve for k and t, that would give t as a function of v, and you can graph it
Answer:
A and D
Step-by-step explanation:
We are given that
(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)





k=
Direct proportion:

Inverse proportion:

Therefore, it is not in direct proportion.






Therefore, 
Hence, the given points form an inverse variation .


Option A and D is true.
Answer:
D.
Step-by-step explanation:
I don't know for a fact but I'm pretty sure its D. sorry if its wrong.
Hope this helped.