Take the homogeneous part and find the roots to the characteristic equation:

This means the characteristic solution is

.
Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form

. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.
With

and

, you're looking for a particular solution of the form

. The functions

satisfy


where

is the Wronskian determinant of the two characteristic solutions.

So you have




So you end up with a solution

but since

is already accounted for in the characteristic solution, the particular solution is then

so that the general solution is
Answer:
3/4→15/20 and 2/5→8/20
Step-by-step explanation:
4*5=20, do what you do to denominator to numerator, so 3*5=15. 15/20. Same for 2/5.
I hope this helps you
12 gallons for 144 miles
6 galoons for 144/2=72 miles
1 gallon for 72/6=12 miles
if 1 gallon for 12 miles
how many gallons for 324 miles
?.12=1.324
?=324/12
?=27 miles
Answer:9 and 21
Step-by-step explanation:I used a calculator