Int var1 = 0b0001; int var2 = 0b1111; int results1 = var1 & var2; int results2 = var1 | var2; int results3 = var1 ^ var2; in
1 answer:
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That’s the answer with steps
ANSWER: y= 3x - 6
STEP-BY-STEP EXPLANATION:
(1,-3) and (3,3)
X1=1 X2=3
Y1= - 3 Y2=3
1) Find the slope of the line.
To find the slope of the line passing through these two points we need to use the slope formula:
m =
m= m=
= 3
2)Use the slope to find the y-intercept.
Now that we know the slope of the line is 3 we can plug the slope into the equation and we get:
y= 3x+b
Next choose one of the two point to plug in for the values of x and y. It does not matter which one of the two points you choose because you should get the same answer in either case. I generally just choose the first point listed so I don’t have to worry about which one I should choose.
y= 3x+b point (1,-3)
-3= 3(1) + b
-3-3=b
-6=b
3)Write the answer.
Using the slope of 3 and the y-intercept of -6 the answer is:
y = 3x - 6
Answer:
Step-by-step explanation:
1.
Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.
2.
Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.
3.
Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,
4.
The same method used to solve problem (3) can be applied to this problem.