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3 years ago

What is the first question

Physics

1 answer:

yanalaym [24]3 years ago

6 0

Distance....................

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A ball is dropped from rest from the top of a cliff that is 15.0 m high. From ground level, a second ball is thrown straight upw

lesya [120]

Answer:

3.75 meters below the top of the cliff.

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3 years ago

How do unemployment impact on an individual's psychological well being?

Natalija [7]

Answer:

Unemployment cause stress which ultimately has long-term physiological health effect

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3 years ago

What is accerlation ?

andre [41]

Explanation:

ability to gain speed over a short period of time.

the formula is:

_ v - v0 <Delta> v

a = _______ = ________

t <Delta> t

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3 years ago

Read 2 more answers

A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t

Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

$KE = PE$

$\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}$

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

$q_{1,2}$ = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

$q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}$

Replacing,

$q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}$

$q_2 = 3.6531nC$

Therefore the charge on the sphere is 3.6531nC

4 0

3 years ago

A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?

olga55 [171]

Answer:

17.6 m/s²

Explanation:

Given:

$v_{f}$ = 90 m/s (final velocity)

$v_{i}$ = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

$a_{avg}$ = Δv / Δt

We can find Δv by doing

Δv = $v_{f}$ - $v_{i}$

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

$a_{avg}$ = Δv / Δt

$a_{avg}$ = $\frac{88m/s}{5/s}$

acceleration = 17.6 $m/s^{2}$

4 0

3 years ago