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Dovator [93]
2 years ago
12

A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?

Physics
1 answer:
olga55 [171]2 years ago
4 0

Answer:

17.6 m/s²

Explanation:

Given:

v_{f} = 90 m/s (final velocity)

v_{i} = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

a_{avg} = Δv / Δt

We can find Δv by doing

Δv = v_{f} - v_{i}

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

a_{avg} = Δv / Δt

a_{avg} = \frac{88m/s}{5/s}

acceleration = 17.6 m/s^{2}

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-- <u>For the toaster:</u>

Power = 1.4 kW  =  1,400 watts

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-- The CFL bulb uses energy at 0.0079 times the rate of the toaster.

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3 years ago
The greater the mass of an object, the greater its force due to gravity
Serga [27]
What is the question?
6 0
3 years ago
An artillery shell is launched on a flat, horizontal field at an angle of α = 40.8° with respect to the horizontal and with an i
Lina20 [59]

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1317.4 m

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Horizontal component of initial speed=v_{ox}=v_0cos\theta=346cos40.8=261.9m/s

Vertical component of initial speed=v_{oy}=346sin40.8=226.1m/s

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Using the  formula

Horizontal distance=261.9\times 5.03

Horizontal distance=1317.4 m

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8 0
2 years ago
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vladimir1956 [14]

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So it's the same with electrons.

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PIT_PIT [208]

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6 0
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