moving the balls closer together
pumping more air into the soccer ball
putting the baseball in a plastic case
Explanation:
The gravitational force between the baseball and the soccer ball will increase if the moving balls are closer together, pumping more air into the soccer ball and putting the baseball in a plastic case.
According to Newton's law of universal gravitation "the force between two masses is proportional to the magnitude of their mass and inversely proportional the square of the distances between them". It is mathematically expressed as:
Fgravity = G
Where G is a constant called the universal gravitation constant.
M1 is the mass of particle 1
M2 is the mass of particle 2
r is the distance between them.
The force of gravity increases as their masses increase and also as the distance between the bodies reduce.
From the options:
Moving the balls closer together distance reducing
Pumping more air into the soccer ball mass increasing
Putting the baseball in a plastic case mass increasing
Learn more:
Universal Gravitation brainly.com/question/1724648
#learnwithBrainly
The properties of acids are: (A), (C) and (D).
Explanation:
Acids taste sour, and most
acids are poisonous. Furthermore, acids react with certain metals to
produce hydrogen gas. Few acids are corrosive as well. The option (B) is not valid because acids react with BASES (not with other acids) to produce salt and water. Hence A, C and D are the correct options.
Answer:
Efficiency = 71%
Explanation:
Given the following data:
Output energy = 250 Joules
Input energy = 350 Joules
To find efficiency;
Substituting into the equation, we have;

Efficiency = 71.43 ≈ 71%
Therefore, the efficiency of the candle is 71 percent.
Hence the expression of ω in terms of m and k is

Given the expressions;

Equating both expressions we will have;

Divide both equations by 2π

Square both sides

Take the square root of both sides

Hence the expression of ω in terms of m and k is
