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N76 [4]
4 years ago
8

State which of the following ordered pairs is a function. Set A: (-1, 0), (-2, 1), (4, 3), (3, 4) Set B: (1, 4), (2, 3), (3, 2),

(4, 1) Set C: (2, 1), (3, 2), (2, 3), (1, 4) a. Set A b. Set B c. Both Set A and Set B d. Set C Please select the best answer from the choices provided
Mathematics
1 answer:
Mice21 [21]4 years ago
6 0

Answer:

Both set A and B.

Step-by-step explanation:

Set A: (-1, 0), (-2, 1), (4, 3), (3, 4)

Set B: (1, 4), (2, 3), (3, 2), (4, 1)

Set C: (2, 1), (3, 2), (2, 3), (1, 4)

In order for (x,y) to be a function, only one x get the value of y, but many x'es can get the value y.

Looking at the set A and B, and the definition above, we can say that they are functions.

What about set C? It is not a function, as x = 2 is equal 1 or 3, which does not meet the condition from the definition.


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