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Mrrafil [7]
3 years ago
10

I am thinking of a number. I multiplied this number by 3, subtracted 8, and doubled the result, then added 14. Then I added on 5

0% of what I had, and then added on 11. Then I divided by 5. After all that, I was left with 8. What number did I start with?
Mathematics
2 answers:
NikAS [45]3 years ago
7 0

The you used was number 6 here why

First you need to do is figure out the full equation as written in the question.

What I did is this:

 

x=starting number

3x                                                                      multiply by 3

3x-8                                                                   subtract by 8

2(3x-8)                                                              double the result

2(3x-8)+14                                                        add 14

2(3x-8)+14+.5(2(3x-8)+14)                               add half of result

2(3x-8)+14+.5(2(3x-8)+14)-11                          subtract 11

2(3x-8)+14+.5(2(3x-8)+14)-11/5=8                divide entire equation by 5 to get the answer of 8

 

Now, solve!

multiply both sides by 5:  

2(3x-8)+14+.5(2(3x-8)+14)-11=40

next thing we want to do is get rid of the first set of parenthesis:

6x-16+14+.5(6x-16+14)-11=40

now get rid of second set of parenthesis:

6x-16+14+3x-8+7-11=40

combine like terms:

(6x+3x)+(-16+14-8+7-11)=40

9x-14=40

add 14 to both sides:

9x=54

divide by 9:

x=6

 

Now, lets check the answer!

6*3=18-8=10*2=20+14=34+17=51-11=40/5=8

 

We got the original final answer so your original number was 6!

Lorico [155]3 years ago
7 0

Answer:

yea what  

106998luna said

Step-by-step explanation:

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