How to subtract radians?

2 answers:

4 0

You first need to make sure the denominators are equal, then when they are, you can add/subtract the numerators. Then you can place the result over the common denominator.

I hope this helps! :)

Mamont248 [21]3 years ago

3 0

Usually radians are represented by a number of π.

Example: 2π or (3π/2) or -π/5, etc.

If I have to add 2π+3π = 5π

if I have to add (3π/2 + π), I reduce to the same denominator:

3π/2 + π ==> 3π/2 + 2/2π ===> 5π/2

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delilah dose 184 jumping jacks in 4 minutes she dose her jumping jacks at a constant rate how many jumping jacks can delilah do

kondaur [170]

Answer: 46 jumping jacks per minute

Step-by-step explanation: Divide the total number of jumping jacks (184) by the time (4 minutes). Since she is going at a constant rate, this would be equal to 46 jumping jacks per minute. On a coordinate plane, this would be a linear function.

5 0

3 years ago

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = xyi + 5zj + 7yk

REY [17]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

where $S$ is the surface with $C$ as its boundary. The curl is

$\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k$

Parameterize $S$ by

$\vec\sigma(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(8-u\cos v)\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Then take the normal vector to $S$ to be

$\vec\sigma_u\times\vec\sigma_v=u\,\vec\imath+u\,\vec k$

Then the line integral is equal to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv$