Your given side ab with a length of 6 centimeters and side bc with a length of 5 centimeters. The measure of amgel A is 30. How
many triangles can you construct using these measurements?
1 answer:
Answer:
2
Step-by-step explanation:
The given angle is opposite the <em>shortest</em> of the given sides, and sin(A) < 5/6, so there are two possible solutions.
The law of sines tells you that angle C will satisfy ...
sin(C)/ab = sin(A)/bc
sin(C) = ab/bc·sin(A) = 6/5·1/2 = 3/5
The given angle is 30°, so the sum of remaining angles must be less than 150°. There are two possible angles less than 150° that have a sine of 3/5:
C₁ = arcsin(3/5) = 36.87°
C₂ = 180° -arcsin(3/5) = 143.13°
You can construct two triangles with the given measurements.
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See the attachments for drawings of them.
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Answer:
a) the length of the wire for the circle =
b)the length of the wire for the square =
c) the smallest possible area = 126.02 in² into two decimal places
Step-by-step explanation:
If one piece of wire for the square is y; and another piece of wire for circle is (60-y).
Then; we can say; let the side of the square be b
so 4(b)=y
b=
Area of the square which is L² can now be said to be;
On the otherhand; let the radius (r) of the circle be;
2πr = 60-y
Area of the circle which is πr² can now be;
Total Area (A);
A =
=
For the smallest possible area;
∴
If we divide through with (2) and each entity move to the opposite side; we have:
By cross multiplying; we have:
2πy = 480 - 8y
collect like terms
(2π + 8) y = 480
which can be reduced to (π + 4)y = 240 by dividing through with 2
∴ since , we can determine for the length of the circle ;
60-y can now be;
=
=
=
=
also, the length of wire for the square (y) ;
The smallest possible area (A) =
= 126.0223095 in²
≅ 126.02 in² ( to two decimal places)