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iragen [17]
4 years ago
12

Your given side ab with a length of 6 centimeters and side bc with a length of 5 centimeters. The measure of amgel A is 30. How

many triangles can you construct using these measurements?

Mathematics
1 answer:
anygoal [31]4 years ago
4 0

Answer:

  2

Step-by-step explanation:

The given angle is opposite the <em>shortest</em> of the given sides, and sin(A) < 5/6, so there are two possible solutions.

The law of sines tells you that angle C will satisfy ...

  sin(C)/ab = sin(A)/bc

  sin(C) = ab/bc·sin(A) = 6/5·1/2 = 3/5

The given angle is 30°, so the sum of remaining angles must be less than 150°. There are two possible angles less than 150° that have a sine of 3/5:

  C₁ = arcsin(3/5) = 36.87°

  C₂ = 180° -arcsin(3/5) = 143.13°

You can construct two triangles with the given measurements.

__

See the attachments for drawings of them.

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Answer:

55.

Step-by-step explanation:

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8 0
3 years ago
In the triangle below, what is the length of the side opposite the 30° angle? Picture and answers in attachment.
Alex17521 [72]

Answer:

The answer to this question is B.

8 0
4 years ago
Find the missing side length
scZoUnD [109]
The answer is 14 or c
7 0
3 years ago
The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole
lozanna [386]

Answer:

A = 0.75 gram or 1 gram

Step-by-step explanation:

The half-life of carbon 14 is years. How much would be left of an original -gram sample after 2,292 years? (To the nearest whole number).

We can use the following formula for half-life of ^{14}C to find out how much is left from the original sample after 2,292 years:  

A = A_{0}e^{-0.000124t}

where:

<em>A</em> is the amount left of an original gram sample after <em>t</em> years, and  

A_{0} is the amount present at time <em>t</em> = 0.

The half-life of  ^{14}C  is the time <em>t</em> at which the amount present is one-half the amount at time <em>t </em>= 0.

If 1 gram of  ^{14}C is present in a sample,  

 Solve for A when t = 2,292:  

Substituting A_{0}  = 1 gram into the decay equation, and we have:  

A = A_{0}e^{-0.000124t}

A = A_{0}e^{-0.000124(2,292)}

A = 0.75 g or 1 g  

6 0
3 years ago
Hep me please and thx u
zubka84 [21]

Answer:

what do i dohere?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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