Answer:
So the final answer is

Step-by-step explanation:
Radicals:
In mathematics, a radical expression is defined as any expression containing a radical (√) symbol. Many people mistakenly call this a 'square root' symbol, and many times it is used to determine the square root of a number. However, it can also be used to describe a cube root, a fourth root, or higher.
The given expression is

Now take common radical out so we will get

Now add the Parenthesis part.

So the final answer is

Ok, i really don't remember this, so i don't want to steer you wrong. maybe wait for another answer?
(2x + 3)⁵
(2x + 3)(2x + 3)(2x + 3)(2x + 3)(2x + 3)(2x + 3)
(2x(2x + 3) + 3(2x + 3))(2x(2x + 3) + 3(2x + 3)(2x + 3)
(2x(2x) + 2x(3) + 3(2x) + 3(3))(2x(2x) + 2x(3) + 3(2x) + 3(3))(2x + 3)
(4x² + 6x + 6x + 9)(4x² + 6x + 6x + 9)(2x + 3)
(4x² + 12x + 9)(4x² + 12x + 9)(2x + 3)
(4x²(4x² + 12x + 9) + 12x(4x² + 12x + 9) + 9(4x² + 12x + 9))(2x + 3)
(4x²(4x²) + 4x²(12x) + 4x²(9) + 12x(4x²) + 12x(12x) + 12x(9) + 9(4x²) + 9(12x) + 9(9))(2x + 3)
(16x⁴ + 48x³ + 36x² + 48x³ + 144x² + 108x + 36x² + 108x + 81)(2x + 3)
(16x⁴ + 48x³ + 48x³ + 36x² + 144x² + 36x² + 108x + 108x + 81)(2x + 3)
(16x⁴ + 96x³ + 216x² + 216x + 81)(2x + 3)
16x⁴(2x + 3) + 96x³(2x + 3) + 216x²(2x + 3) + 216x(2x + 3) + 81(2x + 3)
16x⁴(2x) + 16x⁴(3) + 96x³(2x) + 96x³(3) + 216x²(2x) + 216x²(3) + 216x(2x) + 216x(3) + 81(2x) + 81(3)
32x⁵ + 48x⁴ + 184x⁴ + 288x³ + 432x³ + 648x² + 432x² + 648x + 162x + 243
32x⁵ + 232x⁴ + 720x³ + 1080x² + 810x + 243
5. Given the equation y = (1/4) cos[(2pi/3)*theta]:
5a. For the general equation y = a cos(bx), the period is given by 2pi/b. In this equation, b = 2pi/3, so this means that 2pi/b = 2pi/(2pi/3) = 3. Therefore, the period of this equation is 3, and the cosine wave repeats itself every 3 x-units.
5b. For the general equation y = a cos(bx), the amplitude is given by a. Therefore the amplitude is a = 1/4, and this means that the cosine wave's range is from -1/4 to 1/4 for all values of x.
5c. The equation of the midline is y = 0. This represents the average value over the wave. This is determined by adding the highest and lowest values of the range and taking the average, in this case, 1/4 + (-1/4) = 0, and 0 / 2 = 0. Another way to do this is using the general equation y = a cos(bx) + c, where the midline's equation is y = c. In this case, there is no value of c in the given, implying that c = 0, and the midline is y = 0.
6. Let the horizontal distance be x. Then tan42 = h/x, and h = x tan42. Then using the Pythagorean theorem: 3280^2 = h^2 + x^2
3280^2 = x^2 (tan42)^2 + x^2
3280^2 = x^2 [(tan42)^2 + 1]
x = 2437.52
Therefore, h = x tan42 = 2,194.75 ft.