All categories

3 years ago

Which face has an area of 28 cm2? Face

Mathematics

2 answers:

Alex73 [517]3 years ago

7 0

Answer:

wheres the picture?

Step-by-step explanation:

ira [324]3 years ago

4 0

Answer:

where is the picture?

Step-by-step explanation:

You might be interested in

Which ordered pair is not a point on the graph of y = 1/2 x - 7?

Ivanshal [37]

The answer is a, brainliest?

7 0

2 years ago

Read 2 more answers

Plz help ill give you brainlist to you

Nastasia [14]

First one the answer is A; Alexander needs 70 ft

8 0

3 years ago

6) The sum of three consecutive numbers is 120.<br> What is the smallest of the three numbers ?

bekas [8.4K]

Answer:

Step-by-step explanation:

Let the smallest number be n,

then the three numbers are n, n+1 and n+2

Therefore, n+(n+1)+(n+2)=120

Collecting like terms,

n+n+n=120-1-2

3n=117

n=117/3

n=39

Therefore the numbers are 39,40 and 41.

And the smallest number is 39.

8 0

3 years ago

Name the sets of numbers to which -10 belongs

lesya [120]

1 , 2, 3, -1, -2, -3

6 0

3 years ago

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago