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vlabodo [156]
3 years ago
14

the bathroom shower in celia's house uses 7 gallons of water per minute. if Celia installs a water saving device,the shower will

use only 2 1/2 gallons of water per minute. how many gallons of water will Celia save during a 12-minute shower after the water-saving device is installed
Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0
She saves 54 gallons.
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hichkok12 [17]

Answer:

<em>B.) Kelly got the better deal.</em>

Step-by-step explanation:

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3 years ago
Simplify: 23<br> x2 + 2x2<br> -2)<br> x} + 223<br> ző +225<br> zaś + 2x}<br> 25+ 225
Ilia_Sergeevich [38]

Answer:

x^5/6+2x^7/3

Step-by-step explanation:

hoped this was helpful! c:

7 0
2 years ago
A 1-foot ruler broke into two pieces so that one piece was 5 1/4 inches long. how long was the other piece?
yan [13]
12 - 5.25 = 6.75
The other piece is 6.75 inches long
4 0
3 years ago
Read 2 more answers
Find the equation of the line that contains the point (3,9) and is parallel to the line y=4x+1. Write the line in slope-intercep
Aleksandr-060686 [28]
Y = 4x + 1....slope here is 4. A parallel line will have the same slope

y = mx + b
slope(m) = 4
(3,9)...x = 3 and y = 9
now we sub and find b, the y int
9 = 4(3) + b
9 = 12 + b
9 - 12 = b
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5 0
3 years ago
Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0
2 years ago
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