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Vadim26 [7]
2 years ago
7

how can the number 39 be divided into two parts in order that the sum of 2 upon 3 of one part and 3 upon 4 of the other part is

28
Mathematics
1 answer:
vfiekz [6]2 years ago
3 0

Answer:

The two numbers are 15 and 24

Step-by-step explanation:

Let us assume the two parts be x and y

So according to the question

x + y = 39

(2 ÷ 3) x + (3 ÷ 4)y = 28

or

8x + 9y = 28 × 12

8x + 9 × (39 - x) = 336

-x = 336 - 351

x = 15

And, y = 39 - 15

= 24

Hence, the x and y is 15 and 24 respectively

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Pls help I really don’t know what to da
Vika [28.1K]

Answer:

1. True, 2. False, 3. I am blind.

Step-by-step explanation:

For the 3rd one I cannot confirm becaue I am blind.

8 0
3 years ago
A maker of a certain brand of low-fat cereal barsclaims that the average saturated fat content is 0.5gram. In a random sample of
finlep [7]

Answer:

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

p_v =2*P(t_{(7)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=0.475

The sample deviation calculated s=0.183

We need to conduct a hypothesis in order to check if the true mean is 0.5 or no, the system of hypothesis would be:  

Null hypothesis:\mu = 0.5  

Alternative hypothesis:\mu \neq 0.5  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=8-1=7  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(7)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

4 0
3 years ago
Read 2 more answers
Three stamps can be attached to each other in various ways.how many ways might three stamps be attached?
ivanzaharov [21]
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula. 
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C. 
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space. 
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.


8 0
3 years ago
What is the area of the regular polygon?
BartSMP [9]

Answer:

You could use the polygon area formula OR here's an easier solution

We draw the lines DC and DE

Angle ADC = 120°

Triangle ADC is a 30 60 90 triangle

In such a triangle Line AE = hypotenuse * sq root (3) /2

Line AE = 3 * 0.8660254038  = 2.5980762114

Line DE = 1.5

Area of Triangle ADE = .5 * 1.5 * 2.5980762114 =

1.9485571586   square meters and entire area of Triangle

ABC = 6 * 1.9485571586

which equals 11.6913429513  square meters

Step-by-step explanation:

6 0
2 years ago
Please help asap 50 pts
Gala2k [10]
The volume of the rectangular prism:

V = length × width × height

60x^3+145x^2+70x=5x(12x^2+29x+14)=5x(12x^2+21x+8x+14)\\\\=5x[3x(4x+7)+2(4x+7)]=5x(4x+7)(3x+2)

Answer: A.\ 5x(4x+7)(3x+2)
7 0
3 years ago
Read 2 more answers
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