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Yanka [14]
3 years ago
8

Which integer is closest to 0 on the number line?

Mathematics
2 answers:
Elenna [48]3 years ago
7 0
The answer is C, 1.
In a number line, the larger number it gets, the more of the right side they're. The smaller the number, the more left side they get.
So, on a number line, 1 is just at the right side of 0, all the other options are at least one more place away from 0.
maxonik [38]3 years ago
4 0
It should be choice C.
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I need help in Elementary Statistics
Sonbull [250]

I don't know how to help u if u didn't give a question for me to answers for

3 0
4 years ago
Given the graph of a line y=−x. Write an equation of a line which is parallel and goes through the point (8,2).
serious [3.7K]

The slope of y = -x is m = -1.  Thus, starting with the slope-intercept form y = mx + b, we substitute -1 for m, 8 for x and 2 for y, to determine the vaue of b:

2 = -1(8) + b, or 10 = b.  Then the equation of the line parallel to y = -x and passing thru (8,2) is:

y = -x + 10.

3 0
4 years ago
Which multiplication expression is equivalent to
oee [108]

Answer:

1

Step-by-step explanation:

Correct question:  2x2 - 5x - 3 / 4x2 + 12x + 5 divided by 3x2 - 11x + 6 / 6x2 + 11x - 10.

As given: \frac{(2x^{2}-5x-3) }{(4x^{2}+12x+5 )} \div \frac{(3x^{2} -11x+6)}{(6x^{2}+11x-10) }

Solving it by using quadratic equation.

= \frac{(2x^{2}-6x+1x-3) }{(4x^{2}+10x+2x+5) } \div \frac{(3x^{2}-9x-2x+6 }{(6x^{2}+15x-4x-10) }

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \div \frac{(3x-2) (x-3)}{(2x+5) (3x-2)}

To divide fraction take the reciprocal of divisor and multiply the dividend.

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \times \frac{(2x+5) (3x-2)}{(3x-2) (x-3)}

We solve it to get 1 as it cancel fraction on both side.

Answer is 1.

5 0
3 years ago
Read 2 more answers
2) Evaluate the given numerical expression.<br><br> A) 9<br> B) 12<br> C) 14<br> D) 21
eduard

Answer:

  • \boxed{\sf{14}}

Step-by-step explanation:

\boxed{\underline{\text{ORDER OF OPERATIONS:}}}

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

<u>PEMDAS</u>

  • <u>Parentheses</u>
  • <u>Exponents</u>
  • <u>Multiply</u>
  • <u>Divide</u>
  • <u>Add</u>
  • <u>Subtract</u>

<u>BODMAS</u>

  • <u>Brackets</u>
  • <u>Order</u>
  • <u>Divide</u>
  • <u>Add</u>
  • <u>Subtract</u>

<u>First, do parentheses.</u>

3+6*(5+4)÷3-7

(5+4)=9

\Longrightarrow: \sf{3+6* 9\div 3-7}

<u>Do multiply and divide.</u>

6*9=54

54/3=18

<u>Then, rewrite the problem down.</u>

\Longrightarrow: \sf{3+18-7}

<u>Add.</u>

\sf{3+18=21}

\sf{21-7=\boxed{\sf{14}}

\Longrightarrow: \boxed{\sf{14}}

  • <u>Therefore, the correct answer is "C. 14".</u>

I hope this helps, let me know if you have any questions.

8 0
3 years ago
Solve these equation please
charle [14.2K]

Step-by-step explanation:

I know only 1 Answer

1. p=

3-(-1)(7)/5

3+1(7)/5

3+7/5=10/5=2

p=2 Answer

hope it helps....

3 0
3 years ago
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