Question

Which multiplication expression is equivalent to

Answer 1

Answer:

The answer would be the third option. $\frac{(x+3)(2x+1)}{(2x+1)(2x+5)}$ × $\frac{(2x+5)(3x-2)}{(x-3)(3x-2)}$

Answer 2

Answer:

1

Step-by-step explanation:

Correct question:  2x2 - 5x - 3 / 4x2 + 12x + 5 divided by 3x2 - 11x + 6 / 6x2 + 11x - 10.

As given: $\frac{(2x^{2}-5x-3) }{(4x^{2}+12x+5 )} \div \frac{(3x^{2} -11x+6)}{(6x^{2}+11x-10) }$

Solving it by using quadratic equation.

= $\frac{(2x^{2}-6x+1x-3) }{(4x^{2}+10x+2x+5) } \div \frac{(3x^{2}-9x-2x+6 }{(6x^{2}+15x-4x-10) }$

= $\frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \div \frac{(3x-2) (x-3)}{(2x+5) (3x-2)}$

To divide fraction take the reciprocal of divisor and multiply the dividend.

= $\frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \times \frac{(2x+5) (3x-2)}{(3x-2) (x-3)}$

We solve it to get 1 as it cancel fraction on both side.

Answer is 1.