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Lisa [10]
3 years ago
9

Solve the linear equation: 3(y-1)=2(y+1)​

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

y=5

Step-by-step explanation:

3y-3=2y+2

-2y     -2y

y-3=2

+3    +3

y=5

hope this helps

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Use the laws of Sines and law of cosines to find missing dimensions​
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Answer:

A) ERROR

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Step-by-step explanation:

Houston, We have a problem!!! too much information

If we had a legit triangle, the law of sines would hold

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as this is NOT an equality, the triangle does not exist as described.

IF it did, we'd get different results depending on which set we used

∠F = 180 - 138 - 20 = 22°

Law of sines

19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>

or

8/sin20 =  DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>

If we attempt to use Law of cosines

DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>

so really none is correct because we attempt to use trig calculations to a non-triangle.

12) AC² = 15² + 19² - 2(15)(19)cos120

      AC = 29.51270...

29.51270 / sin120 = 15/sinC

C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>

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