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Svetlanka [38]
3 years ago
12

Which of the following equations is non-linear?

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

2x + 6y = 14y - 19x^2 + 12 is a non-linear equation

Step-by-step explanation:

Lets define a linear equation first.

A linear equation is an equation in which there is no variable with exponent greater than 1 or the degree of the equation is 1.

So,

<u>x + 12 = -8x + 10 - 2y</u>

The equation is a linear equation because the degree of the equation is 1.

<u>x = 8x + 19 - 10y</u>

The equation is a linear equation because the degree of the equation is 1.

<u>2x + 6y = 14y - 19x^2 + 12</u>

The equation involve a term with exponent 2 which makes the degree of the equation 2 making it a quadratic equation

<u>2x + 13y + 14x - 7 = 16y - 3</u>

The equation is a linear equation because the degree of the equation is 1.

Hence,

2x + 6y = 14y - 19x^2 + 12 is a non-linear equation

Keywords: Linear, quadratic

Learn more about equations at:

  • brainly.com/question/5102020
  • brainly.com/question/5147732

#LearnwithBrainly

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Answer:

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=320128 represent the sample mean

\mu population mean (variable of interest)

\sigma=50324 represent the population standard deviation

n=529 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

320128-1.96\frac{50324}{\sqrt{529}}=315839.52    

320128+1.96\frac{50324}{\sqrt{529}}=324416.48    

So on this case the 95% confidence interval would be given by (315839.52;324416.48)    

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