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grandymaker [24]
3 years ago
8

Solve the equation x2 = 10.

Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

\large\boxed{x=-\sqrt{10}\ or\ x=\sqrt{10}}

Step-by-step explanation:

x^2=10\iff x=\pm\sqrt{10}

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18 of the last 30 cars passed you were black. what is the probability the next car will be black?
Nutka1998 [239]
18/30 simplifies into 6/10 which then is put in decimal form of 0.6
7 0
3 years ago
Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
3 years ago
I need help anyone ?? please
Ulleksa [173]

Answer:

you need to show more for help

Step-by-step explanation:

5 0
3 years ago
This set of 3 numbers are measurements of a right triangle. 10,8,6<br><br>True<br>False​
arlik [135]

Answer:

True

Step-by-step explanation:

**plug it in using the Pythagorean Theorem**

6^2+8^2= 10^2

36+64=100

100=100 (true)

7 0
3 years ago
Read 2 more answers
Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in \frac{6}{5} hr

Pump A and C can fill tank in \frac{3}{2} hr

Pump B and C can fill tank in 2 hr

Let A be the total hr taken A therefore rate of A=\frac{1}{A} /hr

Let B be the total hr taken B therefore rate of B=\frac{1}{B} /hr

Let C be the total hr taken C therefore rate of C=\frac{1}{C} /hr

\frac{1}{A}+\frac{1}{B}=\frac{5}{6}-----1

\frac{1}{B}+\frac{1}{C}=\frac{1}{2}-----2

\frac{1}{A}+\frac{1}{C}=\frac{2}{3}-----3

Adding 1,2 & 3

2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1

thus time taken by A,B and C combined is 1 hr

7 0
3 years ago
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