Given that Jon said,
"m-1 is always greater than 1-m"
we want to find how true the statement is;

secondly for negative values of m;

So, the statement "m-1 is always greater than 1-m" is false.
Because 1- m is greater than m-1 when m is a negative integer.
Therefore, I Disagree, because 1- m is greater than m-1 when m is a negative integer
Answer:
First option: 6y^2sqrt(10) + 12sqrt(5y)
Step-by-step explanation:
3sqrt(10) * (2y^2 + 2sqrt(2y)
= 6y^2sqrt(10) + 6sqrt(20y)
= 6y^2sqrt(10) + 12sqrt(5y)
I believe it would be the 3rd one.
Answer:
If Regina wants a mean of 90, she needs to sell 94 books on the 5th day.