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Elan Coil [88]
4 years ago
7

Which expression is equivalent to ( 5 ^ -2)^5 × 5^4​

Mathematics
2 answers:
lapo4ka [179]4 years ago
8 0

Answer:

C

Step-by-step explanation:

(5^-2)^5 * 5^4

5^-10 *5^4

5^-6

1/5^6

inna [77]4 years ago
5 0

<em>so</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

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Lesson 1.6 Problem Solving
wel

Answer:

Easy! It's 59(or 58.5).

4 0
4 years ago
After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.
REY [17]

Answer:

C(t) = $28,000(0.811)^t  (Answer A)

Step-by-step explanation:

The value of the car is decreasing.  Thus, by the end of the first year of ownership, the car will have the value $28,000(1 -0.189)^1, where the "-0.189" represents DECAY instead of GROWTH.

Please use " ^ " to indicate exponentiation.

Then the desired formula is C(t) = $28,000(0.811)^t  (Answer A)

4 0
3 years ago
Solve the triangle given that a=19 b=16, c=11.
kirill [66]

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle (a, b, c), but all angles are unknown (A, B, C). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that a = 19, b = 16 and c = 11, then the missing angles are, respectively:

Angle A

a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A (1)

A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)

A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right]

A \approx 87.395^{\circ}

Angle B

b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B (2)

B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)

B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right]

B\approx 57.271^{\circ}

Angle C

C = 180^{\circ}-A-B

C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}

C = 35.334^{\circ}

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

8 0
3 years ago
John painted 4/5 of his house the first day and 1/10 of the house the next day. What fraction of his house is left to paint?
Westkost [7]
Convert fifths into tenths: every one fifth equals two tenths

4*2=8...8/10 + 1/10=9/10

9/10-10/10=1/10

He has 1/10 left to paint
4 0
3 years ago
Make t the subject of k= t-e/2
Sophie [7]

Answer:

t=k+\frac{e}{2}

Step-by-step explanation:

k=t-\frac{e}{2}\\t=k+\frac{e}{2}

5 0
3 years ago
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