9514 1404 393
Answer:
- Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
- Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E
Step-by-step explanation:
The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.
The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.
__
<em>Additional comment</em>
The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.
Answer:
Yes ,because (x+1) is the factor of all degree 4 polynomial
Hey there!
5 x w = 10 to the second power . . .
10 x 10 = 100
5 x 100 = 500
5 x w = 500
500 = 5w
w = 100 <-------
Hope this helps you.
Have a great day!
The domain will be the integer numbers between 8 and 12 using the limits in other words 8 ≤ u ≤ 12
this is considering every player will bought only one uniform for the season
Answer: B is Greater Than A.
Step-by-step explanation: um hm.
