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Mumz [18]
3 years ago
6

Let W= { (x, y, z) |x=1|; y, z ∈ℝ } Prove that W is a subspace of ∈ℝ How can I resolve this ?

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

W is not a subspace.

Step-by-step explanation:

Notice that (-1,2,2) and (-1,5,3) are both elements of W. Because its x coordinate, x = -1, satisfy the condition |x| = 1.

but (-1,2,2) + (-1,5,3) = (-2,7,5) do not belongs to W. Because its first coordinate, x =-2, do not satisfy |x| = 1.  

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OLEGan [10]
Yes, what do you need help with?
5 0
3 years ago
A rectangle is shown below.
Dahasolnce [82]

Answer:

  a)  247.25 cm²

  b)  62.0 cm

Step-by-step explanation:

All of these upper-bound/lower-bound problems are worked the same way. The bounds on the measurement are presumed to be half of one unit of the least-significant digit.

Here, the least significant digit of both numbers is in the "units" place, so the maximum error is presumed to be 1/2 unit, or ±0.5 cm.

If the measurement were 7.36 inches, the least significant digit is in the hundredths place, so the maximum error is presumed to be half a hundredth, or ±0.5 × 0.01 inches = ±0.005 inches.

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To find the bounds on the measurement, you add or subtract this maximum error from the measurement. So, for the measurements in this problem, the maximum and minimum they can be are ...

  21 cm: minimum of 21 - 0.5 = 20.5 cm; maximum of 21 + 0.5 = 21.5 cm

  11 cm: minimum of 10.5 cm; maximum of 11.5 cm

If you wanted to express these as an inequality, you'd have to remember that half-units are rounded up, so the inequalities would be ...

  20.5 cm ≤ long side < 21.5 cm

  10.5 cm ≤ short side < 11.5 cm

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a) The area is computed as the product of the rectangle's side length measurements. The area will be a maximum when both measurements are a maximum:

  Amax = (21.5 cm)(11.5 cm)

  Amax = 247.25 cm²

__

b) The perimeter is twice the sum of the lengths of two adjacent sides of the rectangle. The minimum perimeter will be the sum using the minimum side lengths, or ...

  Pmin = 2(20.5 cm +10.5 cm) = 2(31.0 cm)

  Pmin = 62.0 cm

_____

<em>Comment on measurement bounds</em>

You have to remember that these concepts are mathematical in nature, so only an approximation of the real world. If you have ever used a tape measure to measure a distance of any length, you will have discovered a couple of things:

  • different tape measures are different lengths
  • the measurement you make depends on how tight you stretch the tape (and often, on temperature and/or humidity)
  • it is amazingly hard to choose the "nearest" measurement when the value is halfway between marks on the tape. (That is, there is some fuzziness in the boundary between nearest units.)

So, mathematically, there will be very specific definitions and procedures to follow regarding measurement values. In the real world, you have to remember these are only an approximation to reality, hopefully a useful one.

7 0
3 years ago
Stephanie had 7/8 pound of birdseed she use 3/8 pound to fill the birdfeeder how much birdseed to Stephanie have left?
marusya05 [52]

Answer:

4/8 or 1/2

Step-by-step explanation:

7/8-3/8= 4/8 or 1/2

3 0
2 years ago
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Answer:
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Step-by-step explanation:
We have formula Y - y 1 = m ( X --x1) => Y - 10 = 3(X-4)
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2 years ago
I need help on this 2 please help​
Dovator [93]

Answer:

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midpoint=(x1+x22,y1+y22)

Step-by-step explanation:

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