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lidiya [134]
10 months ago
13

The value of an explanatory variable is 14, while the corresponding value ofthe response variable is 9. What would be the coordi

nates of this data pointwhen plotted on a scatterplot?A. (23,9)B. (9,23)C. (14,9)D. (9,14)
Mathematics
1 answer:
Tomtit [17]10 months ago
3 0

Answer:

C. (14, 9)

Explanation:

The coordinates of the data are usually in the following order

(explanatory variable, response variable)

In this case, the explanatory variable is 14 and the response variable is 9, so the point will be

C. (14, 9)

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Solve the system of equations.
Tom [10]

Easiest method you can apply (Cramer's one). <em>"</em><em>Thanks</em><em> </em><em>me</em><em>"</em><em> </em>if i've been helpful

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3 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
2 years ago
A ball is thrown into the air. The height h, in feet, of the ball after x seconds is given by the function h = −16(x − 2)2 + 72.
Anon25 [30]

Answer:

A. -16x²+64x+8

B. 72 ft.

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B. Find the abs. max. by looking back at the vertex form. The max is (2,72). Use the y-value for the height.

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3 years ago
Which is bigger, one-fifth of 35 or two-sixths of 24?
GREYUIT [131]

Answer:

two-sixths of 24

Step-by-step explanation:

7<8

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3 years ago
The graph shows the locations of an eagles nest, a tree, and a pond. on the coordinate grid, each unit represents a mile.​
katrin2010 [14]

Answer:

use triangle

Step-by-step explanation:

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2 years ago
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