<h3>
Answer: w^2 + 3w - 10</h3>
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Work Shown:
Let x = w-2
This will allow us to replace the (w-2) with x to get...
(w-2)(w+5)
x(w+5)
x*w + x*5 ... distribute
w(x) + 5(x)
Now replace x with w-2 and distribute again
w(x) + 5(x)
w(w-2) + 5(w-2)
w*w + w*(-2) + 5*w + 5*(-2)
w^2 - 2w + 5w - 10
w^2 + 3w - 10
Answer:
2^{3} +1⋅4−3 = 9
2^{0}+10−4⋅2 = 3
3+5^{2} -6⋅4 = 4
Step-by-step explanation:
To find out time interval δt we need to substract initial time from the final time. In this question first number in the coordinates representes time:
δt=50 - 0
δt= 50s
TIme interval is 50s.
Answer:
ewfyeet
Step-by-step explanation:
