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Eduardwww [97]
3 years ago
15

An initial investment of $100 is now valued at $150. The annual interest rate is 5%, compounded

Mathematics
1 answer:
Alika [10]3 years ago
5 0

Answer:

  8 years

Step-by-step explanation:

100e^(.05t) = 150 . . . . . a better model of the situation

e^(.05t) = 150/100 . . . . divide by 100

0.05t = ln(1.5) . . . . . . . . take natural logs

t = ln(1.5)/0.05 ≈ 8.11 . . . . divide by the coefficient of t

The money has been invested for about 8 years.

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Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

           =     \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

By using

        (ab)ⁿ = aⁿbⁿ

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= 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

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2 years ago
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