We see from the attached, that kite area = product of the diagonals / 2
The diagonals could be 12 by 8 or
6 by 16 or
3 by 32, etc
It cannot be narrowed down any further.
Answer:
x^4-3x^3+x^2-4
Step-by-step explanation:
Given the following functions
R(x) = 2x^4 – 3x^3 + 2x – 1 and
C(x) = x^4 – x^2 + 2x + 3
We are to find the profit function P(x)
P(x) = R(x) - C(x)
P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)
P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3
Collect the like terms
P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3
P(x) = x^4-3x^3+x^2+0-4
P(x) = x^4-3x^3+x^2-4
Hence the required profit function P(x) is x^4-3x^3+x^2-4
Answer:
i)16
ii)9
Step-by-step explanation:
![\sqrt{256} \\=\sqrt{16*16} \\=16\\\\ii)\ \sqrt[3]{729}\\ =\sqrt[3]{9*9*9} \\=9](https://tex.z-dn.net/?f=%5Csqrt%7B256%7D%20%5C%5C%3D%5Csqrt%7B16%2A16%7D%20%5C%5C%3D16%5C%5C%5C%5Cii%29%5C%20%5Csqrt%5B3%5D%7B729%7D%5C%5C%20%3D%5Csqrt%5B3%5D%7B9%2A9%2A9%7D%20%5C%5C%3D9)
For this case we must write in algebraic symbology the expression described above:
We have an equation, then:
- x squared plus y squared:
- minus 2x plus 7y plus 1:
- equals zero:
We construct the equation:
Answer:
Answer:
A.) 2.54
Step-by-step explanation:
I think this is the answer
