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3 years ago

hello I am trying to figure out how much rent I would have to pay if I abated the rent 30%. My rent is $610.

1 answer:

6 0

If you were to get 30% backed off, lucky you !
You would then pay only the remaining 70%.

70% means 0.70

0.70 x $610 = $427 

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What is m, 2/3 × 4/5 = 1/3÷ m

ankoles [38]

Answer:

$\frac{2}{3} \times \frac{4}{5} = \frac{1}{3} \div m \\ \frac{8}{15} = \frac{1}{3m} \\ \frac{8}{5} = \frac{1}{m} \\ 8m = 5 \\ m = \frac{5}{8} \\$

4 0

3 years ago

Read 2 more answers

Each package of pens contains 3 pens. How is the number of pens related to the number of packages?

yuradex [85]

Answer: The correct option is (C) Packages x 3 = Pens

Step-by-step explanation: Given that each package of pens contains 3 pens.

We are to choose the correct mathematical relation between number of pens and number of packages.

Let, n represents the number of pens and N represents the number of packages.

Then, according to the given information, we have

$n\times 3=N\\\\\Rightarrow \textup{Packages}\times 3=\textup{Pens}.$

Thus, the correct relation is

Packages x 3 = Pens.

Option (C) is CORRECT.

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3 years ago

20/60+15/60=35/60> What dose it equal

stepladder [879]

Answer:

$\dfrac{7}{12}$

Step-by-step explanation:

1. Find the Greatest Common Factor of the numerator and denominator.

The prime factors of 35 are 5, 7, 35

The prime factors of 60 are 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The only common factor of 35 and 60 is 5.

2. Divide the numerator and denominator by the Greatest Common Factor.

$\dfrac{35}{60} = \mathbf{\dfrac{7}{12}}$

8 0

3 years ago

Find the midpoint of a segment whose endpoints are (9, –7) and (–3, 5).

suter [353]

For this question, you would have to use the midpoint formula.
(X1 +X2 / 2 , Y1 + Y2 / 2)

In other words,
(9 + -3 / 2 , -7 +5 / 2)
(6 / 2 , -2 / 2)
(3 , -1)

Your midpoint is (3, -1)

7 0

3 years ago

What is the measure, in degree, of angle z ?

Jobisdone [24]

Answer:

55°

Step-by-step explanation:

if the middle is straight, then x+35°=90°

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3 years ago