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Verdich [7]
3 years ago
15

What is the 50th term in the sequence 17, 14, 11, 8, ...

Mathematics
1 answer:
Fed [463]3 years ago
8 0
The answer would be -142, because you have to keep subtracting 3 and I got -142
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Solving equations 10z+3z+5=2(z-3)
Nesterboy [21]

Answer: Use the PEMDAS rule

Step-by-step explanation: 0z+3z+5=2(z-3)=

z= -1

you need to do the z numbers all together and the normal numbers together then subtract them to get -1

I hope that I help you

5 0
3 years ago
PLEASE HELP PLEASE PLEASE PLEASE
sleet_krkn [62]

Answer:

oh no that's tough bro

hope you get through

8 0
2 years ago
Solve by completing the square:
laiz [17]
The answer is 4 trust me bro
8 0
2 years ago
Lily forgot the security code for her apartment building. the code is two different numbers followed by a letter. how many diffe
umka21 [38]
Assuming the keypad has all 26 letters and the numbers 1-9 there are 2106 possible codes

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8 0
3 years ago
The class sizes of the introductory psychology courses at a college are shown below 121,134,106,93,149,130,119,128 the college a
frozen [14]
Center : Mean  Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5  After the introduction of the new course, center =  average(121,134,106,93,149,130,119,128,45) = 113.9  The center has moved to the left (if plotted in a graph) because of the low intake for the new course.  Spread before introduction of the new course :  Arrange the numbers in ascending order:  (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132  Spread = Interquartile range = Q3-Q1 = 19.5  After addition of the new course,

 (45,93, 106,119,) 121, (128, 130,134, 149)
 Q1=median(45,93,106,119)=99.5
 Q3=median (128, 130,134, 149)= 132
 Spread = Interquartile range = 132-99.5 =32.5 
 We see that the spread has increased after the addition of the new course.
3 0
3 years ago
Read 2 more answers
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