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r-ruslan [8.4K]

3 years ago

5

What is the value of x? Please explain...

1 answer:

docker41 [41]3 years ago

5 0

Answer:
X=14

Explanation:
The question tells us that the triangle is an equilateral triangle, meaning all of its side lengths are equal.

The perimeter of the triangle is all the lengths added together, so we can say this:

Perimeter=3(1.75x-2)

And since the question tells us the perimeter, we can input that into the equation as well.

67.5= 3(1.75x-2)

And now we solve:

67.5= 3(1.75x-2)
Distribute 3 into the parentheses
67.5=5.25x-6
Combine like terms (move -6 to the other side)
67.6+6=5.25x
73.6=5.25x
Divide both sides by 5.25
73.6/5.25=5.25x/5.25
14=x

I hope this helps! Please comment if you have any questions.

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First one:
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i hope this is helpful
have a nice day

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You compare the sizes of two MP3 players. The old model is 34 inch thick. The new model is 25 inch thick. How much thinner is th

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Answer:

22

Step-by-step explanation:

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4 years ago

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2 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago