I can help with the first problems!
Answer:
(c) $80
Step-by-step explanation:
Each discounted price corresponds to the original price multiplied by a factor related to the discount. For a discount fraction of 'd', the multiplier is (1 -d).
This means you can use any of the lines in the table to find the original price.
<u>5% disount</u>: (1 -5%)·p = $76 . . . . where p is the original price
p = $76/0.95 = $80 . . . . . . . the original price
<u>10% discount</u>: (1 -10%)·p = $72
p = $72/0.90 = $80
<u>25% discount</u>: (1 -25%)·p = $60
p = $60/0.75 = $80
_____
<em>Additional comment</em>
The table values for 5% and 10% differ by 5% and $4. That means 5% of the original price is $4. There are two things you can do with this:
- add back that 5% to the 5%-discounted price: $76 +4 = $80
- multiply that 5% by 20 to get 100% of the original price: 20(5%) = 20($4) ⇒ 100% = $80.
Answer:
x=2 y=-4
Step-by-step explanation:
-2x=y
-x-6x=-14
-7x=-14
x=2
Answer:
The probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

The information provided is:
<em>p</em> = 0.60
<em>n</em> = 100
As <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportions.
The distribution of sample proportion is
.
Compute the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% as follows:


Thus, the probability that in a random sample of 100 CSU graduates the error is within 5% of the population proportion of 60% is 0.6923.
Ok fracion 5/100 decimal .05