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3 years ago

Activity where are you going

Mathematics

1 answer:

Vaselesa [24]3 years ago

3 0

Answer:

I will center school one year from now despite the fact that my acumen is far more noteworthy than the normal sixth grader

You might be interested in

Can anyone help solve this?

Mashcka [7]

Answer:

12.2

Step-by-step explanation

The triangles are congruent, so the sides are as well. Add 6.1 and 6.1 and you will get 12.2

5 0

2 years ago

A triangle is to be dilated with the origin as the center of dilation and with a scale factor of 2. Which answer choice correctl

saveliy_v [14]

Answer:

All the coordinates are changed to

(x, y) ⇒ (2x, 2y)

Step-by-step explanation:

Given - A triangle is to be dilated with the origin as the center of dilation and with a scale factor of 2.

To find - Which answer choice correctly maps this dilation algebraically?

Proof -

Let ABC is a triangle where A, B, C are the vertices of the triangle respectively.

Now,

Let the coordinates be (x, y)

If a triangle is to be dilated with the origin as the center of dilation and with a scale factor of a , then the coordinated be changes as

(x, y) ⇒ (ax, ay)

Here given , a = 2

So, all the coordinates are changed to

(x, y) ⇒ (2x, 2y)

3 0

2 years ago

Help! I can't seem to answer this. (question in photo)

german

The answer would be 48...

4 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Can you answer these for me ?

vodka [1.7K]

Answer:

B. 4 3/8

Step-by-step explanation:

7/8 X 5 = 4 3/8

6 0

2 years ago

Activity where are you going​

Activity where are you going