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3 years ago

Activity where are you going

Mathematics

1 answer:

Vaselesa [24]3 years ago

3 0

Answer:

I will center school one year from now despite the fact that my acumen is far more noteworthy than the normal sixth grader

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(2t^(3)+3t-4)-(4t^(2)-6t)

Gnoma [55]

−

Step-by-step explanation:

3 0

3 years ago

Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standa

inessss [21]

Answer:

a) 0.4164

Step-by-step explanation:

Mean lifespan (μ) = 18.8 days

Standard deviation (σ) = 2 days

For any given lifespan 'X', the z-score is:

$z=\frac{X- \mu}{\sigma} \\z=\frac{X- 18.8}{2}$

For X=12.04 days:

$z=\frac{12.04 - 18.8}{2} \\z=-3.38$

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.

For X=18.38 days:

$z=\frac{18.38 - 18.8}{2} \\z=-0.21$

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.

The probability that a butterfly lives between 12.04 and 18.38 days is

$P=41.68-0.036\\P=41.64\%\ or\ 0.4164$

6 0

3 years ago

Which statement is true about the given information?

Lubov Fominskaja [6]

Answer

∴ The true statement is Answer:

The true statement is BD ≅ CE ⇒ 3rd answer

Step-by-step explanation:

- There is a line contained points B , C , D , E

- All points are equal distance from each other

- That means the distance of BC equal the distance of CD and equal

the distance of DE

∴ BC = CD = DE

- That means the line id divided into 3 equal parts, each part is one

third the line

∴ BC = 1/3 BE

∴ CD = 1/3 BE

∴ DE = 1/3 BE

∵ BC = CD

∴ C is the mid-point of BD

∴ BC = 1/2 BD

∵ CD = DE

∴ D is the mid-point of DE

∴ CD = 1/2 CE

- Lets check the answers

* BD = one half BC is not true because BC = one half BD

* BC = one half BE is not true because BC = one third BE

* BD ≅ CE is true because

BD = BC + CD

CE = CD + DE

BC ≅ DE and CD is common

then BD ≅ CE

* BC ≅ BD is not true because BC is one half BD

∴ The true statement is BD ≅ CE

plz mark me brainliest

5 0

2 years ago

A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo

katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the box $V=x^2z$

Volume of the box $=12 ft^3\\$

$Therefore, x^2z=12\\z=\frac{12}{x^2}$

The material for the base costs $\$0.17/ft^2$ , the material for the sides costs $\$0.10/ft^2$ , and the material for the top costs $\$0.13/ft^2$ .

Area of the base $=x^2$

Cost of the Base $=\$0.17x^2$

Area of the sides $=4xz$

Cost of the sides= $=\$0.10(4xz)$

Area of the Top $=x^2$

Cost of the Base $=\$0.13x^2$

Total Cost, $C(x,z) =0.17x^2+0.13x^2+0.10(4xz)$

Substituting $z=\frac{12}{x^2}$

$C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}$

To minimize C(x), we solve for the derivative and obtain its critical point

$C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2$

Recall: $z=\frac{12}{x^2}=\frac{12}{2^2}=3\\$

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0

3 years ago

I need help please!!!

myrzilka [38]

the slope of the given point is m=−3/4

5 0

10 months ago

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Activity where are you going